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DP IB Physics: HL

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Home / IB / Physics: HL / DP / Topic Questions / 9. Wave Phenomena (HL only) / 9.2 Single-Slit Diffraction / Structured Questions


9.2 Single-Slit Diffraction

Question 1a

Marks: 3

A source of sound is placed in front of a barrier that has an opening of width comparable to the wavelength of the sound.

9-2-hl-sq-medium-q1a-diag

A sound detector is moving along the line PQ. The centre PQ is marked X.

(a)

(i)
On the axis below, sketch a graph to show how the intensity, I of the sound varies as the detector moves from P to Q.
9-2-hl-sq-medium-q1ai-diag

[2]

(ii)
State the effect on the intensity pattern of decreasing the wavelength of sound.

[1]

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    Key Concepts
    Slit Width

    Question 1b

    Marks: 3
    (b)
    The angle between the slit, X and the first location after X where sound is not detected is 102.8°.  The slit has a width of 4 mm. 

       (i)    Calculate the wavelength of the sound used in this experiment.         

    [1]

       (ii)   Calculate the path difference of the sound from both slits at this point.        

    [2]

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      Question 1c

      Marks: 4

      The width of the slit is now increased. Now, when the sound detector is moving along the line PQ, sound is detected at P, then at X and then at Q.

      (c)

      (i)
      Explain the effects of a wider slit on the diffraction pattern.

      [2]

      (ii)

      Label the points P, X and Q on the horizontal axis of the graph shown.

      9-2-hl-sq-medium-q1cii-diag

      [2]

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        Question 1d

        Marks: 4

        (d)     The slit width is now 30 m. The same source of sound is used throughout.

        (i)
        Calculate the angle between the slit, X, and the first location where sound is detected after X.  

        [2]

        (ii)
        Explain how moving the screen further away will change the interference pattern.    

        [2]

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          Question 2a

          Marks: 4

          The formula for the position of the first minimum of the diffraction pattern produced by a single slit is given by:

          theta equals lambda over b

          (a)
          Using the conditions for interference, derive this formula. 

          [4]

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            Question 2b

            Marks: 3

            The frequency of monochromatic light passing through a slit is 2.44 × 1014 Hz. The screen is located 3.75 m from the single slit. The distance on the screen from the central maximum to the first minimum is 0.25 cm.

            (b)
            Find the slit width. 

            [3]

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              Question 2c

              Marks: 4

              Three diffraction patterns, x, y and z, are produced from three wavelengths of light, λ, 5λ and 10λ, passing through a slit of fixed width b

              9-2-hl-sq-medium-q2c-diag

              (c)
                
              (i)
                     State the wavelength of light that produced each diffraction pattern, x, y and z. 

              [2]

              (ii)
              Explain which pattern has the highest intensity at the central maximum and state how to increase the intensity at the central maximum.

              [2]

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                Key Concepts
                Slit Width

                Question 2d

                Marks: 2

                The graph below shows the variation of light intensity, I with angular displacement θ on a screen placed far away from a narrow slit.

                9-2-hl-sq-medium-q2d-diag

                (d)
                Draw the variation of light intensity, I with angular displacement θ on a screen when the narrow slit is been made even narrower. 

                [2]

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                  Question 3a

                  Marks: 3

                  Plane wavefronts of monochromatic light of wavelength λ are incident on a rectangular slit of width b. The light is brought to a focus after passing through the slit on a screen at a distance D from the slit as shown in the diagram below. 

                  The width of the slit is comparable to the wavelength of the light and ≪ D. The point X on the screen is opposite the centre of the slit.  9-2-hl-sq-medium-q3-diag

                  The variation of the intensity incident on the screen with angle θ is shown on the graph below.

                  9-2-hl-sq-medium-q3-graph 

                   

                  (a)
                  Explain the shape of the intensity distribution in terms of the conditions for interference. 

                  [3]

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                    Question 3b

                    Marks: 3
                    (b)

                    The angular half-width of the central maximum for this intensity distribution is given by the expression φ lambda over b where θ = φ. 

                    Derive an expression for the half-width, d, of the central maximum using the terms, Dλ and b.

                    [3]

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                      Question 3c

                      Marks: 2

                      In a single-slit diffraction experiment, the slit width is 0.030 mm and the wavelength of the light incident on the slit is 525 nm.

                      (c)
                      Calculate the angle of diffraction for the second maxima.

                      [2]

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                        Question 3d

                        Marks: 3

                        The single slit of width b is replaced with rectangular slits, of width 2. The intensity distribution of a single slit is shown by the dotted line.

                        9-2-hl-sq-medium-q3d

                        (d)
                        Draw a sketch within the central maxima of the single slit of the new intensity distribution on the screen. 
                        [3]
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                          Question 4a

                          Marks: 3

                          An experiment is set up where white light is incident on a single slit. 

                          (a)
                          The white light illuminates the slit. The first diffraction minimum for a wavelength of 630 nm is observed at 12°. 
                           
                          (i)
                          Calculate the slit width.
                          [1]
                          (ii)
                          Describe and explain what would happen to the diffraction angle if the slit width was made narrower.
                          [2]

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                            Question 4b

                            Marks: 4
                            (b)

                            (i)
                            Identify the first secondary maximum and the second diffraction minimum on the single slit intensity graph below.
                            9-2-hl-sq-medium-q4b-diag
                            [2]

                            (ii)
                            Determine the wavelength of light for which the first secondary maximum occurs at an angle of 12°.

                            [2]

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                              Question 4c

                              Marks: 3
                              (c)
                              Explain why the central maximum is white but the first secondary maximum at 12° is coloured.
                              [3]
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                                Question 4d

                                Marks: 3
                                (d)
                                Explain the pattern of the colours seen on the screen between 12° and the next minima.
                                [3]
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                                  Question 5a

                                  Marks: 2

                                  A rectangular slit has width b and is comparable to the wavelength λ of plane wavefronts of monochromatic light incident upon it. After passing through the slit, the light is brought to a focus on a screen. 

                                  9-2-hl-sq-medium-q5-diag

                                  The diagram shows a line normal to the plane of the slit, drawn from the centre of the slit to the screen is labelled PQ. The points X and Y are the first points of minimum intensity as measured from point Q. 

                                  The diagram also shows two rays of light incident on the screen at point X. Ray RX leaves one edge of the slit and ray PX leaves the centre of the slit. The angle φ is small. 

                                  (a)
                                  On the diagram, label two angles of diffraction.
                                  [2]
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                                    Question 5b

                                    Marks: 4
                                    (b)
                                    Derive an expression, in terms of λ, for the path difference RT between the rays RX and RT.
                                    [4]
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                                      Question 5c

                                      Marks: 4
                                      (c)
                                      Describe the changes in the experimental setup that would decrease the width of the central bright maximum.

                                      [4]

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                                        Question 5d

                                        Marks: 2

                                        In a certain demonstration of single-slit diffraction λ = 400 nm, b = 0.12 mm, and the screen is a long way from the slit. 

                                        (d)
                                        Calculate the angular width of the central maximum of the diffraction pattern on the screen.

                                        [2]

                                         

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