The conductor in the diagram in part (a) has a length of 1.2 m and a current of 0.85 A flowing through it. The conductor is placed at 30o to the B field, which has a magnetic flux density of 70 mT.
When the force, the magnetic field and the current are all mutually perpendicular to each other, the directions of each can be interpreted using a technique known as Fleming's Left Hand Rule.
A wire of length 15 cm has a mass of 30 g and current of 2.0 A flowing through it. When the wire is placed inside a uniform magnetic field it 'floats' in equilibrium in the magnetic field.
(c)
(i)
Calculate the weight of the wire
[3]
(ii)
Hence determine the size of the force produced by the magnetic field acting on the wire when it is carrying current
When a moving charge enters a magnetic field the magnetic field produces a force on the charge, which can be calculated using
where q = charge, v = velocity, B = magnetic flux density, and θ = the angle between the velocity of the charge and the direction of the magnetic field.
The magnetic force provides the centripetal force which causes the charge to move in a circular orbit. The equation to calculate centripetal force acting on an object is
where m = mass of the object, v = speed of the object and r = radius of the circular orbit.
(a)
Using the equations given above, show that the radius of the circular orbit of the charged object inside the magnetic field can be given as
An electron is travelling at right angles to a uniform magnetic field which has a magnetic flux density of 5.6 mT. The speed of the electron is 3.0 × 106 m s–1.
(c)
Use the following information to calculate the radius of the circular orbit of the electron: