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DP IB Chemistry: HL

Topic Questions

Home / IB / Chemistry: HL / DP / Topic Questions / 17. Equilibrium (HL only) / 17.1 The Equilibrium Law / Multiple Choice: Paper 1


17.1 The Equilibrium Law

Question 1

Marks: 1

The Haber process is a key step in the manufacture of fertilisers:

N2 (g) + 3H2 (g) rightwards harpoon over leftwards harpoon 2NH3 (g)         ΔH = -ve

Which is correct about the effect of increasing temperature for this reaction?

  Effect on equilibrium position Effect on Kc
A. Shifts left No change
B. Shifts right No change
C. Shifts right Increase
D. Shifts left Decrease

    Choose your answer
      

    Question 2

    Marks: 1

    Which equation represents a reaction where the number of moles alone can not be used to calculate the value of Kc?

    • CH3CH2OH (aq) + CH3COOH (aq) rightwards harpoon over leftwards harpoon CH3CH2OCOCH3 (aq)  + H2O (l)

    • H2 (g) + I2 (g) rightwards harpoon over leftwards harpoon 2HI (g)

    • 2SO2 (g) + O2 (g) rightwards harpoon over leftwards harpoon 2SO3 (g)

    • N2 (g) + O2 (g) rightwards harpoon over leftwards harpoon 2NO (g)

    Choose your answer
      
    Key Concepts
    Equilibrium Problems

    Question 3

    Marks: 1

    When 0.20 mol NO, 0.08 mol H2 and 0.10 mol of H2O are placed in a 1.0 dm3 flask, the following equilibrium is established:

    2NO (g) + 2H2 (g) rightwards harpoon over leftwards harpoon N2 (g) + 2H2O (g)

    At equilibrium, the concentration of H2 (g) was found to be 0.02 mol dm-3.

    What is the correct calculation to work out Kc?

    • Kcfraction numerator stretchy left square bracket 0.14 stretchy right square bracket squared stretchy left square bracket 0.02 stretchy right square bracket squared over denominator stretchy left square bracket 0.03 stretchy right square bracket to the power of blank stretchy left square bracket 0.16 stretchy right square bracket squared end fraction

    • Kcfraction numerator open square brackets 0.03 close square brackets open square brackets 0.16 close square brackets squared over denominator open square brackets 0.14 close square brackets squared open square brackets 0.02 close square brackets squared end fraction

    • Kcfraction numerator begin mathsize 14px style stretchy left square bracket 0.03 stretchy right square bracket stretchy left square bracket 0.06 stretchy right square bracket squared end style over denominator begin mathsize 14px style stretchy left square bracket 0.06 stretchy right square bracket squared stretchy left square bracket 0.06 stretchy right square bracket squared end style end fraction

    • Kcfraction numerator begin mathsize 14px style stretchy left square bracket 0.06 stretchy right square bracket stretchy left square bracket 0.16 stretchy right square bracket squared end style over denominator begin mathsize 14px style stretchy left square bracket 0.14 stretchy right square bracket squared stretchy left square bracket 0.04 stretchy right square bracket squared end style end fraction

    Choose your answer
      
    Key Concepts
    Equilibrium Problems

    Question 4

    Marks: 1

    Nitrogen dioxide can form a dimer that can also break back down again as part of a reversible reaction:

    N2O4 (g) rightwards harpoon over leftwards harpoon NO2 (g)         ΔH = +ve

    The reaction reaches an equilibrium at temperature T, where Kc = 1

    What is true for a higher temperature, T2?

      Kc value ΔGθ value
    A. Increases Increases
    B. Decreases Increases
    C. Decreases Decreases
    D. Increases Decreases
      Choose your answer
        

      Question 5

      Marks: 1

      Which would be the correct way to plot a graph and then calculate ΔGθ from experimental data of Kc and temperature values?

      ΔGθ = -RT ln K

        y-axis x-axis ΔGθ =
      A. 1 / T ln K -R x gradient
      B. ln K 1 / T -R x gradient
      C. ln K 1 / T R / gradient
      D. 1 / T ln K R / gradient
        Choose your answer