0%

DP IB Chemistry: HL

Topic Questions

Home / IB / Chemistry: HL / DP / Topic Questions / 12. Atomic Structure (HL only) / 12.1 Electrons in Atoms / Multiple Choice: Paper 1


12.1 Electrons in Atoms

Question 1

Marks: 1

Which statement is true about the spectra shown? hydrogen-spectrum-hl

  • All the lines in R have the same energy

  • Q and S could represent line emission spectra

  • Only S could represent a line emission spectrum for hydrogen

  • P indicates the element has 4 pairs of electrons at different energy levels 

Choose your answer
  

Question 2

Marks: 1

The energy absorbed at the limit of convergence for helium is 19.6 x 10-18 J per atom.

Which calculation would be used to calculate the wavelength, in m, for this electron transition?

(c = 3.00 x 108 ms-1, h = 6.63 x 10-34 Js)

  • λ = fraction numerator 19.6 space cross times space 10 to the power of negative 18 end exponent space cross times space 3.00 space cross times space 10 to the power of 8 over denominator 6.63 space cross times space 10 to the power of negative 34 end exponent end fraction

  • λ = fraction numerator 3.00 space cross times 10 to the power of 8 space cross times 6.63 space cross times space 10 to the power of negative 34 end exponent space over denominator 19.6 space cross times space 10 to the power of negative 18 end exponent end fraction

  • λ =  fraction numerator 19.6 space cross times space 10 to the power of negative 18 end exponent space cross times space 6.63 space cross times space 10 to the power of negative 34 end exponent over denominator 3.00 space cross times space 10 to the power of 8 end fraction

  • λ = fraction numerator 3.00 space cross times space 10 to the power of 8 over denominator 19.6 space cross times space 10 to the power of negative 18 end exponent space cross times 6.63 space cross times space 10 to the power of negative 34 end exponent end fraction

Choose your answer
  

Question 3

Marks: 1

The first ionisation energies (in kJ mol-1) of five successive elements are:

2081, 496, 738, 578, 787

What could these elements be?

  • First five elements in a period

  • Second to the sixth elements in a period

  • Last four elements of one period and the first one of the next period

  • Last element of one period and the first four elements of the next period

Choose your answer
  
Key Concepts
Trends Across a Period

Question 4

Marks: 1

A period 3 element forms an oxide M2O3.

Which represents the first four successive ionisation energies of M?

  Ionisation energy / kJmol-1
  First Second Third Fourth
A. 496 4560 6940 9540
B. 578 1820 2740 11600
C. 1012 1907 2914 4964
D. 736 1450 7740 10500

    Choose your answer
      

    Question 5

    Marks: 1

    Between which ionisation energies of silicon will there be the greatest difference?

    • Between the second and fourth ionisation energies

    • Between the first and third ionisation energies

    • Between the fourth and fifth ionisation energies

    • Between the fifth and sixth ionisation energies

    Choose your answer