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DP IB Chemistry: HL

Topic Questions

Home / IB / Chemistry: HL / DP / Topic Questions / 16. Chemical Kinetics (HL only) / 16.1 Rate Expression & Reaction Mechanism / Multiple Choice: Paper 1


16.1 Rate Expression & Reaction Mechanism

Question 1

Marks: 1

The potential energy level profile for the hydrolysis of a tertiary halogenoalkane is shown.

energy-level-profile---tertiary-halogenoalkane-hydrolysis-

Which of the following conclusions can be deduced from the potential energy level profile?

  1. The reaction proceeds via an SN1 mechanism 
  2. The reactants are more stable than the products
  3. The rate-determining step is the first step of the reaction mechanism
  • I and II only 

  • I and III only 

  • II and III only

  • I, II and III

Choose your answer
  

Question 2

Marks: 1

The rate information below was obtained for the following fourth order reaction at a constant temperature: 

5Br (aq) + BrO3 (aq) + 6H+ (aq) → 3Br2 (aq) + 3H2O (l)

conc-v-rate-graph- time-v-conc-graph-bromide-ions

Which rate expression is consistent with the data?

  • Rate = k [Br-] [BrO3-] [H+]

  • Rate = k [Br-]2 [H+]2

  • Rate = k [Br-] [BrO3-] [H+]2

  • Rate = k [Br-]2 [BrO3-] [H+]

Choose your answer
  

Question 3

Marks: 1

The rate information below was obtained for the following reaction at a constant temperature: 

C2H5Br (aq) + OH (aq) → C2H5OH (aq) + Br (aq)

[C2H5Br] / mol dm-3

[OH-] / mol dm-3 

Rate / mol dm-3 s-1

2.0 x 10-3

1.0 x 10-2

4.0 x 10-4 

4.0 x 10-3

1.0 x 10-2

8.0 x 10-4 

8.0 x 10-3

2.0 x 10-2

3.2 x 10-3 


What is the correct equation to calculate the value of the rate constant, k?

  • fraction numerator rate over denominator left square bracket straight C subscript 2 straight H subscript 5 Br right square bracket space left square bracket OH to the power of minus right square bracket end fraction

  • fraction numerator left square bracket straight C subscript 2 straight H subscript 5 Br right square bracket space left square bracket OH to the power of minus right square bracket over denominator rate end fraction

  • fraction numerator rate over denominator left square bracket straight C subscript 2 straight H subscript 5 Br right square bracket space left square bracket OH to the power of minus right square bracket squared end fraction

  • fraction numerator rate over denominator left square bracket straight C subscript 2 straight H subscript 5 Br right square bracket squared space left square bracket OH to the power of minus right square bracket squared end fraction

Choose your answer
  

Question 4

Marks: 1

The mechanism for the following reaction between nitrogen(II) oxide and carbon monoxide is shown.

NO2 (g) + CO (g) → NO (g) + CO2 (g)

 

      Step 1:   NO2 + NO2 ⇌ N2O4   fast step

      Step 2:   N2O4 + 2CO → 2NO + 2CO2   slow step

Which rate expression is consistent with the mechanism?

  • Rate = k [NO2] [CO]2

  • Rate = k [N2O4] [CO]2

  • Rate = k [NO2]2 [CO]2

  • Rate = k [N2O4] [CO]

Choose your answer
  
Key Concepts
Mechanism Problems

Question 5

Marks: 1

The rate information below was obtained for the following reaction of aqueous solutions of F and G, in the presence of a homogeneous catalyst, H, 

2F + 3G → J + 2K

When the concentrations of F and G are doubled, the rate of reaction increases by a factor of four.

When the concentrations of F and H are doubled, the rate of reaction increases by a factor of eight.

Which rate expression is consistent with the data?

  • Rate = k [F]2 [G]3

  • Rate = k [F]2 [H]

  • Rate = k [F] [G] [H]

  • Rate = k [F]2 [H]2

Choose your answer