12.1 Electrons in Atoms

Question 1

Marks: 1

Which of the following calculations gives the correct calculation to find the energy, in kJ, for a photon of blue light given the wavelength ƛ = 550 nm.

h = 6.626 x 10⁻³⁴J s; c = 2.988 x 10⁸ m s^-1

$\frac{6.626 \times 10^{- 34} \times 2.988 \times 10^{8}}{550 \times 10^{- 9}}$
$\frac{6.626 \times 10^{- 34} \times 2.988 \times 10^{8}}{550 \times 1000}$
$\frac{6.626 \times 10^{- 34} \times 2.988 \times 10^{8}}{550 \times 10^{- 9} \times 1000}$
$\frac{6.626 \times 10^{- 34} \times 2.988 \times 10^{8}}{2.988 \times 10^{8} \times 1000}$

Key Concepts

Calculating First Ionisation Energy

Question 2

Marks: 1

Successive ionisation energies for an element, Y, are shown in the table below.

Electrons removed	1st	2nd	3rd	4th	5th
Ionisation energy / kJ mol^-1	736	1450	7740	10500	13600

What is the most likely formula for the ion of Y?

Y⁺
Y²⁺
Y³⁺
Y⁴⁺

Key Concepts

Successive Ionisation Energies

Question 3

Marks: 1

Values for the successive ionisation energies for an unknown element are given in the table below.

First ionisation energy / kJ mol^-1	Second ionisation energy / kJ mol^-1	Third ionisation energy / kJ mol^-1	Fourth ionisation energy / kJ mol^-1
420	3600	4400	5900

In which group of the periodic table would the unknown element be found?

Key Concepts

Deducing the Group

Question 4

Marks: 1

The graph shows the first ionisation energies of some consecutive elements

x-and-y-ionisation-energies Which statement is correct?

Y is in group 13
Y is in group 10
X is in group 15
X is in group 18

Key Concepts

Trends Across a Period

Question 5

Marks: 1

Which transition on the diagram corresponds to the ionisation of hydrogen in the ground state?

ionisation-of-ground-state-hydrogen

Key Concepts

Convergence Limits on an Emission Spectrum

DP IB Chemistry: HL

Topic Questions

12.1 Electrons in Atoms

Question 1

Key Concepts

Question 2

Key Concepts

Question 3

Key Concepts

Question 4

Key Concepts

Question 5

Key Concepts

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