16.2 Activation Energy

1 2 3 4 5

Question 1

Marks: 1

The graph below shows ln k against $\frac{1}{T}$ for a general reaction.

HCE15yK1_ln-k-vs-1overt-question

Which of the lines shows the highest activation energy compared to the original graph?

stemW_j6_ln-k-vs-1overt-answer-options

Key Concepts

Graphing the Arrhenius Equation

Question 2

Marks: 1

The following information was obtained for the rate constant, k, for a reaction at 298 K.

A	E_a	R
2.57 × 10⁹ s^–1	96.2 kJ mol^–1	8.31 J K^–1 mol^–1

Which expression correctly represents how to calculate the rate constant, k?

$2.57 x 10^{9} x e^{(- 96200 / 8.31 x 298)}$
$2.57 x 10^{9} x e^{(- 96.2 / 8.31 x 298)}$
$2.57 x 10^{9} x e^{(8.31 x 298 / - 96.2)}$
$2.57 x 10^{9} x e^{(8.31 x 298 / - 96200)}$

Key Concepts

The Arrhenius Equation

Question 3

Marks: 1

example-arrhenius-plot

Which of the following statements about the Arrhenius plot are not correct?

ln A has an approximate value of -4.7
The gradient of the line is $\frac{- E_{a}}{R}$
The units for the x-axis are K^-1
The equation of the line is ln k = $\frac{- E_{a}}{R T}$ + ln A

Key Concepts

Graphing the Arrhenius Equation

Question 4

Marks: 1

Which term from the Arrhenius equation has the incorrect units?

	Term	Units
A.	E_a	J mol^-1
B.	R	J K^-1 mol^-1
C.	T	K^-1
D.	e	No units

Key Concepts

The Arrhenius Equation

Question 5

Marks: 1

example-arrhenius-plot-2

What is the gradient of the graph?

+ E_a
- E_a
$\frac{- E_{a}}{R}$
$\frac{+ E_{a}}{R}$

Key Concepts

Graphing the Arrhenius Equation

DP IB Chemistry: HL

Topic Questions

16.2 Activation Energy

Question 1

Key Concepts

Question 2

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Question 3

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Question 4

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Question 5

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