Write down $f'(x)$.

By differentiating $f({x^2})$, obtain an expression for the derivative of $\int_0^{{x^2}} {\ln (2 + \sin t){\text{d}}t}$ with respect to $x$.

Hence obtain an expression for the derivative of $\int_x^{{x^2}} {\ln (2 + \sin t){\text{d}}t}$ with respect to $x$.

$\ln (2 + \sin x)$    A1

Note:     Do not accept $\ln (2 + \sin t)$.

[1 mark]

attempt to use chain rule     (M1)

$\frac{{\text{d}}}{{{\text{d}}x}}\left( {f({x^2})} \right) = 2xf'({x^2})$    (A1)

$= 2x\ln \left( {2 + \sin ({x^2})} \right)$    A1

[3 marks]

$\int_x^{{x^2}} {\ln (2 + \sin t){\text{d}}t = \int_0^{{x^2}} {\ln (2 + \sin t){\text{d}}t - \int_0^x {\ln (2 + \sin t){\text{d}}t} } }$    (M1)(A1)

$\frac{{\text{d}}}{{{\text{d}}x}}\left( {\int_x^{{x^2}} {\ln (2 + \sin t){\text{d}}t} } \right) = 2x\ln \left( {2 + \sin ({x^2})} \right) - \ln (2 + \sin x)$    A1

[3 marks]

Many candidates answered this question well. Many others showed no knowledge of this part of the option; candidates that recognized the Fundamental Theorem of Calculus answered this question well. In general the scores were either very low or full marks.

Many candidates answered this question well. Many others showed no knowledge of this part of the option; candidates that recognized the Fundamental Theorem of Calculus answered this question well. In general the scores were either very low or full marks.

Many candidates answered this question well. Many others showed no knowledge of this part of the option; candidates that recognized the Fundamental Theorem of Calculus answered this question well. In general the scores were either very low or full marks.