Date | May 2014 | Marks available | 12 | Reference code | 14M.3ca.hl.TZ0.3 |
Level | HL only | Paper | Paper 3 Calculus | Time zone | TZ0 |
Command term | Find | Question number | 3 | Adapted from | N/A |
Question
Each term of the power series \(\frac{1}{{1 \times 2}} + \frac{1}{{4 \times 5}}x + \frac{1}{{7 \times 8}}{x^2} + \frac{1}{{10 \times 11}}{x^3} + \ldots \) has the form \(\frac{1}{{b(n) \times c(n)}}{x^n}\), where \(b(n)\) and \(c(n)\) are linear functions of \(n\).
(a) Find the functions \(b(n)\) and \(c(n)\).
(b) Find the radius of convergence.
(c) Find the interval of convergence.
Markscheme
(a) \(b(n) = 3n + 1\) A1
\(c(n) = 3n + 2\) A1
Note: \(b(n)\) and \(c(n)\) may be reversed.
[2 marks]
(b) consider the ratio of the \({(n + 1)^{{\text{th}}}}\) and \({n^{{\text{th}}}}\) terms: M1
\(\frac{{3n + 1}}{{3n + 4}} \times \frac{{3n + 2}}{{3n + 5}} \times \frac{{{x^{n + 1}}}}{{{x^n}}}\) A1
\(\mathop {{\text{lim}}}\limits_{n \to 0} \frac{{3n + 1}}{{3n + 4}} \times \frac{{3n + 2}}{{3n + 5}} \times \frac{{{x^{n + 1}}}}{{{x^n}}}x\) A1
radius of convergence: \(R = 1\) A1
[4 marks]
(c) any attempt to study the series for \(x = -1\) or \(x = 1\) (M1)
converges for \(x = 1\) by comparing with p-series \(\sum {\frac{1}{{{n^2}}}} \) R1
attempt to use the alternating series test for \(x = -1\) (M1)
Note: At least one of the conditions below needs to be attempted for M1.
\(\left| {{\text{terms}}} \right| \approx \frac{1}{{9{n^2}}} \to 0\) and terms decrease monotonically in absolute value A1
series converges for \(x = -1\) R1
interval of convergence: \(\left[ { - 1,{\text{ 1}}} \right]\) A1
Note: Award the R1s only if an attempt to corresponding correct test is made;
award the final A1 only if at least one of the R1s is awarded;
Accept study of absolute convergence at end points.
[6 marks]