Date | November 2011 | Marks available | 5 | Reference code | 11N.3ca.hl.TZ0.1 |
Level | HL only | Paper | Paper 3 Calculus | Time zone | TZ0 |
Command term | Find | Question number | 1 | Adapted from | N/A |
Question
Find limx→12((14−x2)cotπx).
Markscheme
using l’Hôpital’s Rule (M1)
limx→12((14−x2)cotπx)=limx→12[−2−πcosec2πx] A1A1
=−1−πcosec2π2=1π (M1)A1
[5 marks]
Examiners report
This question was accessible to the vast majority of candidates, who recognised that L’Hôpital’s rule was required. However, some candidates omitted the factor π in the differentiation of cotπx. Some candidates replaced cotπx by cosπx/sinπx, which is a valid method but the extra algebra involved often led to an incorrect answer. Many fully correct solutions were seen.