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Date May 2017 Marks available 2 Reference code 17M.3ca.hl.TZ0.2
Level HL only Paper Paper 3 Calculus Time zone TZ0
Command term Find Question number 2 Adapted from N/A

Question

Let the Maclaurin series for tanxtanx be

tanx=a1x+a3x3+a5x5+tanx=a1x+a3x3+a5x5+

where a1a1, a3a3 and a5a5 are constants.

Find series for sec2xsec2x, in terms of a1a1, a3a3 and a5a5, up to and including the x4x4 term

by differentiating the above series for tanxtanx;

[1]
a.i.

Find series for sec2xsec2x, in terms of a1a1, a3a3 and a5a5, up to and including the x4x4 term

by using the relationship sec2x=1+tan2xsec2x=1+tan2x.

[2]
a.ii.

Hence, by comparing your two series, determine the values of a1a1, a3a3 and a5a5.

[3]
b.

Markscheme

(sec2x=) a1+3a3x2+5a5x4+(sec2x=) a1+3a3x2+5a5x4+     A1

[1 mark]

a.i.

sec2x=1+(a1x+a3x3+a5x5+)2sec2x=1+(a1x+a3x3+a5x5+)2

=1+a21x2+2a1a3x4+=1+a21x2+2a1a3x4+     M1A1

 

Note:     Condone the presence of terms with powers greater than four.

 

[2 marks]

a.ii.

equating constant terms: a1=1a1=1     A1

equating x2x2 terms: 3a3=a21=1a3=133a3=a21=1a3=13     A1

equating x4x4 terms: 5a5=2a1a3=23a5=2155a5=2a1a3=23a5=215     A1

[3 marks]

b.

Examiners report

[N/A]
a.i.
[N/A]
a.ii.
[N/A]
b.

Syllabus sections

Topic 9 - Option: Calculus » 9.6
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