Date | May 2017 | Marks available | 3 | Reference code | 17M.3ca.hl.TZ0.2 |
Level | HL only | Paper | Paper 3 Calculus | Time zone | TZ0 |
Command term | Hence and Determine | Question number | 2 | Adapted from | N/A |
Question
Let the Maclaurin series for tanx be
tanx=a1x+a3x3+a5x5+…
where a1, a3 and a5 are constants.
Find series for sec2x, in terms of a1, a3 and a5, up to and including the x4 term
by differentiating the above series for tanx;
Find series for sec2x, in terms of a1, a3 and a5, up to and including the x4 term
by using the relationship sec2x=1+tan2x.
Hence, by comparing your two series, determine the values of a1, a3 and a5.
Markscheme
(sec2x=) a1+3a3x2+5a5x4+… A1
[1 mark]
sec2x=1+(a1x+a3x3+a5x5+…)2
=1+a21x2+2a1a3x4+… M1A1
Note: Condone the presence of terms with powers greater than four.
[2 marks]
equating constant terms: a1=1 A1
equating x2 terms: 3a3=a21=1⇒a3=13 A1
equating x4 terms: 5a5=2a1a3=23⇒a5=215 A1
[3 marks]