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Date May 2011 Marks available 3 Reference code 11M.2.sl.TZ1.1
Level SL only Paper 2 Time zone TZ1
Command term Find Question number 1 Adapted from N/A

Question

The following diagram shows triangle ABC .


AB = 7 cm, BC = 9 cm and AˆBC=120 .

Find AC .

[3]
a.

Find BˆAC .

[3]
b.

Markscheme

evidence of choosing cosine rule     (M1)

e.g. a2+b22abcosC

correct substitution     A1

e.g. 72+922(7)(9)cos120

AC=13.9 (=193)     A1     N2

[3 marks]

a.

METHOD 1

evidence of choosing sine rule     (M1)

e.g. sinˆABC=sinˆBAC

correct substitution     A1

e.g. sinˆA9=sin12013.9

ˆA=34.1     A1     N2

METHOD 2

evidence of choosing cosine rule     (M1)

e.g. cosˆA=AB2+AC2BC22(AB)(AC)

correct substitution     A1

e.g. cosˆA=72+13.92922(7)(13.9)

ˆA=34.1     A1     N2

[3 marks]

b.

Examiners report

The majority of candidates were successful with this question. Most correctly used the cosine rule in part (a) and the sine rule in part (b). Some candidates did not check that their GDC was set in degree mode while others treated the triangle as if it were right angled. A large number of candidates were penalized for not leaving their answers exactly or to three significant figures.

a.

The majority of candidates were successful with this question. Most correctly used the cosine rule in part (a) and the sine rule in part (b). Some candidates did not check that their GDC was set in degree mode while others treated the triangle as if it were right angled. A large number of candidates were penalized for not leaving their answers exactly or to three significant figures.

b.

Syllabus sections

Topic 3 - Circular functions and trigonometry » 3.6 » The cosine rule.
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