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Date May 2013 Marks available 3 Reference code 13M.2.sl.TZ2.3
Level SL only Paper 2 Time zone TZ2
Command term Find Question number 3 Adapted from N/A

Question

The following diagram shows a triangle ABC.


The area of triangle ABC is 8080 cm2 , AB =18=18 cm , AC =x=x cm and BˆAC=50B^AC=50 .

Find xx .

[3]
a.

Find BC.

[3]
b.

Markscheme

correct substitution into area formula     (A1)

eg   12(18x)sin5012(18x)sin50

setting their area expression equal to 8080     (M1)

eg   9xsin50=809xsin50=80

x=11.6x=11.6     A1     N2

[3 marks]

a.

evidence of choosing cosine rule     (M1)

eg   c2=a2+b2+2absinCc2=a2+b2+2absinC

correct substitution into right hand side (may be in terms of xx)     (A1)

eg   11.62+1822(11.6)(18)cos5011.62+1822(11.6)(18)cos50

BC =13.8=13.8     A1     N2

[3 marks]

b.

Examiners report

The vast majority of candidates were very successful with this question. A small minority drew an altitude from C and used right triangle trigonometry. Errors included working in radian mode, assuming that the angle at C was 9090, and incorrectly applying the order of operations when evaluating the cosine rule.

a.

The vast majority of candidates were very successful with this question. A small minority drew an altitude from C and used right triangle trigonometry. Errors included working in radian mode, assuming that the angle at C was 9090, and incorrectly applying the order of operations when evaluating the cosine rule.

b.

Syllabus sections

Topic 3 - Circular functions and trigonometry » 3.6 » Solution of triangles.
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