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Date May 2016 Marks available 3 Reference code 16M.2.sl.TZ2.2
Level SL only Paper 2 Time zone TZ2
Command term Demonstrate and Find Question number 2 Adapted from N/A

Question

The following diagram shows a quadrilateral ABCD.

M16/5/MATME/SP2/ENG/TZ2/02

AD=7cm,BC=8cm,CD=12cm,DˆAB=1.75radians,AˆBD=0.82radians.

Find BD.

[3]
a.

Find DˆBC.

[3]
b.

Markscheme

evidence of choosing sine rule     (M1)

egasinA=bsinB

correct substitution     (A1)

egasin1.75=7sin0.82

9.42069

BD=9.42 (cm)     A1     N2

[3 marks]

a.

evidence of choosing cosine rule     (M1)

egcosB=d2+c2b22dc, a2=b2+c22bccosB

correct substitution     (A1)

eg82+9.4206921222×8×9.42069, 144=64+BD216BDcosB

1.51271

DˆBC=1.51 (radians) (accept 86.7°)     A1     N2

[3 marks]

b.

Examiners report

Most candidates solved part (a) correctly, recognizing the need for the law of sines.

a.

In part (b), some recognized they had to use cosine rule but substituted incorrectly. There were a few who used Pythagoras theorem or overly long approaches using the sine rule for 2(b).

Some used the calculator in degree mode instead of radian mode, not recognizing that the angles were given in radians.

b.

Syllabus sections

Topic 3 - Circular functions and trigonometry » 3.6 » The cosine rule.
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