| Date | May 2014 | Marks available | 1 | Reference code | 14M.1.hl.TZ2.12 |
| Level | HL | Paper | 1 | Time zone | TZ2 |
| Command term | Question number | 12 | Adapted from | N/A |
Question
Which molecule is trigonal bipyramidal in shape?
A. \({\text{PC}}{{\text{l}}_{\text{3}}}\)
B. \({\text{SiC}}{{\text{l}}_{\text{4}}}\)
C. \({\text{PC}}{{\text{l}}_{\text{5}}}\)
D. \({\text{S}}{{\text{F}}_{\text{6}}}\)
Markscheme
C
Examiners report
[N/A]
Syllabus sections
Additional higher level (AHL) » Topic 14: Chemical bonding and structure » 14.1 Covalent bonding and electron domain and molecular geometries
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