Date | May 2017 | Marks available | 3 | Reference code | 17M.2.hl.TZ2.4 |
Level | HL | Paper | 2 | Time zone | TZ2 |
Command term | Discuss | Question number | 4 | Adapted from | N/A |
Question
Bonds can be formed in many ways.
Bonds can be formed in many ways.
The equilibrium for a mixture of NO2 and N2O4 gases is represented as:
2NO2(g) \( \rightleftharpoons \) N2O4(g)
At 100°C, the equilibrium constant, Kc, is 0.21.
Discuss the bonding in the resonance structures of ozone.
Deduce one resonance structure of ozone and the corresponding formal charges on each oxygen atom.
The first six ionization energies, in kJ mol–1, of an element are given below.
Explain the large increase in ionization energy from IE3 to IE4.
At a given time, the concentration of NO2(g) and N2O4(g) were 0.52 and \(0.10{\text{ mol}}\,{\text{d}}{{\text{m}}^{ - 3}}\) respectively.
Deduce, showing your reasoning, if the forward or the reverse reaction is favoured at this time.
Comment on the value of ΔG when the reaction quotient equals the equilibrium constant, Q = K.
Markscheme
lone pair on p orbital «of O atom» overlaps/delocalizes with pi electrons «from double bond»
both O–O bonds have equal bond length
OR
both O–O bonds have same/1.5 bond order
OR
both O–O are intermediate between O–O AND O=O
both O–O bonds have equal bond energy
Accept “p/pi/\(\pi \) electrons are delocalized/not localized”.
[3 marks]
ALTERNATIVE 1:
FC: –1 AND +1 AND 0
ALTERNATIVE 2:
FC: 0 AND +1 AND –1
Accept any combination of lines, dots or crosses to represent electrons.
Do not accept structure that represents 1.5 bonds.
Do not penalize missing lone pairs if already penalized in 3(b).
If resonance structure is incorrect, no ECF.
Any one of the structures with correct formal charges for [2 max].
[2 marks]
Any two of:
IE4: electron in lower/inner shell/energy level
OR
IE4: more stable/full electron shell
IE4: electron closer to nucleus
OR
IE4: electron more tightly held by nucleus
IE4: less shielding by complete inner shells
Accept “increase in effective nuclear charge” for M2.
[2 marks]
«Qc = \(\frac{{0.10}}{{{{0.52}^2}}}\) =» 0.37
reaction proceeds to the left/NO2(g) «until Q = Kc»
OR
reverse reaction «favoured»
Do not award M2 without a calculation for M1 but remember to apply ECF.
[2 marks]
ΔG = 0
reaction at equilibrium
OR
rate of forward and reverse reaction is the same
OR
constant macroscopic properties
[2 marks]