Date | November 2020 | Marks available | 2 | Reference code | 20N.1.SL.TZ0.S_10 |
Level | Standard Level | Paper | Paper 1 | Time zone | Time zone 0 |
Command term | Find | Question number | S_10 | Adapted from | N/A |
Question
The following diagram shows part of the graph of , for .
Let be any point on the graph of . Line is the tangent to the graph of at .
Line intersects the -axis at point and the -axis at point B.
Find in terms of and .
Show that the equation of is .
Find the area of triangle in terms of .
The graph of is translated by to give the graph of .
In the following diagram:
- point lies on the graph of
- points , and lie on the vertical asymptote of
- points and lie on the horizontal asymptote of
- point lies on the -axis such that is parallel to .
Line is the tangent to the graph of at , and passes through and .
Given that triangle and rectangle have equal areas, find the gradient of in terms of .
Markscheme
(A1)
A1 N2
[2 marks]
attempt to use point and gradient to find equation of M1
eg
correct working leading to answer A1
eg
AG N0
[2 marks]
METHOD 1 – area of a triangle
recognizing at (M1)
correct working to find -coordinate of null (A1)
eg
-coordinate of null at (may be seen in area formula) A1
correct substitution to find area of triangle (A1)
eg
area of triangle A1 N3
METHOD 2 – integration
recognizing to integrate between and (M1)
eg
correct integration of both terms A1
eg
substituting limits into their integrated function and subtracting (in either order) (M1)
eg
correct working (A1)
eg
area of triangle A1 N3
[5 marks]
Note: In this question, the second M mark may be awarded independently of the other marks, so it is possible to award (M0)(A0)M1(A0)(A0)A0.
recognizing use of transformation (M1)
eg area of triangle = area of triangle , gradient of gradient of , one correct shift
correct working (A1)
eg area of triangle
gradient of area of rectangle
valid approach (M1)
eg
correct working (A1)
eg
correct expression for gradient (in terms of ) (A1)
eg
gradient of is A1 N3
[6 marks]