Date | May 2017 | Marks available | 3 | Reference code | 17M.2.AHL.TZ1.H_2 |
Level | Additional Higher Level | Paper | Paper 2 | Time zone | Time zone 1 |
Command term | Determine | Question number | H_2 | Adapted from | N/A |
Question
The curve C is defined by equation xy−lny=1, y>0.
Find dydx in terms of x and y.
[4]
a.
Determine the equation of the tangent to C at the point (2e, e)
[3]
b.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
y+xdydx−1ydydx=0 M1A1A1
Note: Award A1 for the first two terms, A1 for the third term and the 0.
dydx=y21−xy A1
Note: Accept −y2lny.
Note: Accept −yx−1y.
[4 marks]
a.
mT=e21−e×2e (M1)
mT=−e2 (A1)
y−e=−e2x+2e
−e2x−y+3e=0 or equivalent A1
Note: Accept y=−7.39x+8.15.
[3 marks]
b.
Examiners report
[N/A]
a.
[N/A]
b.