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Date May 2019 Marks available 3 Reference code 19M.2.SL.TZ2.T_5
Level Standard Level Paper Paper 2 Time zone Time zone 2
Command term Find Question number T_5 Adapted from N/A

Question

Consider the function f(x)=13x3+34x2x1.

Find f(x).

[3]
d.

Find the gradient of the graph of y=f(x) at x=2.

[2]
e.

Find the equation of the tangent line to the graph of y=f(x) at x=2. Give the equation in the form ax+by+d=0 where, ab, and dZ.

[2]
f.

Markscheme

x2+32x1      (A1)(A1)(A1)

Note: Award (A1) for each correct term. Award at most (A1)(A1)(A0) if there are extra terms.

[3 marks]

d.

22+32×21     (M1)

Note: Award (M1) for correct substitution of 2 in their derivative of the function.

6     (A1)(ft)(G2)

Note: Follow through from part (d).

[2 marks]

e.

83=6(2)+c     (M1)

Note: Award (M1) for 2, their part (a) and their part (e) substituted into equation of a straight line.

c=283

OR

(y83)=6(x2)     (M1)

Note: Award (M1) for 2, their part (a) and their part (e) substituted into equation of a straight line.

OR

y=6x283(y=6x9.33333)     (M1)

Note: Award (M1) for their answer to (e) and intercept 283 substituted in the gradient-intercept line equation.

18x+3y+28=0  (accept integer multiples)     (A1)(ft)(G2)

Note: Follow through from parts (a) and (e).

[2 marks]

f.

Examiners report

[N/A]
d.
[N/A]
e.
[N/A]
f.

Syllabus sections

Topic 5—Calculus » SL 5.1—Introduction of differential calculus
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Topic 2—Functions
Topic 5—Calculus

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