DP Mathematics SL Questionbank

Points of inflexion with zero and non-zero gradients.
Description
[N/A]Directly related questions
- 17M.2.sl.TZ2.8d: Let R be the region enclosed by the graph of f , the x-axis, the line x=b and...
- 17M.2.sl.TZ2.8c.ii: Find the the rate of change of f at B.
- 17M.2.sl.TZ1.10c: Let d be the vertical distance from a point on the graph of h to the line y=x....
- 17M.2.sl.TZ1.10b.ii: Hence, find the area of the region enclosed by the graphs of h and h−1.
- 17M.2.sl.TZ1.10b.i: Find ∫3.310.111(h(x)−x)dx.
- 17M.2.sl.TZ1.10a.iii: Write down the value of k.
- 17M.2.sl.TZ1.10a.i: Write down the value of q;
- 17M.2.sl.TZ1.10a.ii: Write down the value of h;
- 16M.1.sl.TZ1.9c: The graph of f is transformed by a vertical stretch with scale factor 1ln3....
- 16M.1.sl.TZ1.9b: Find f(x), expressing your answer as a single logarithm.
- 16M.1.sl.TZ1.9a: Find the x-coordinate of P.
- 16N.2.sl.TZ0.10c: (i) Find w. (ii) Hence or otherwise, find the maximum positive rate of change of g.
- 16N.2.sl.TZ0.10b: (i) Write down the value of k. (ii) Find g(x).
- 16N.2.sl.TZ0.10a: (i) Find the value of c. (ii) Show that b=π6. (iii) Find the...
- 08N.1.sl.TZ0.6c: Show that B corresponds to a point of inflexion on the graph of f .
- 08M.1.sl.TZ1.8c: Find the x-coordinate of N.
- 08M.2.sl.TZ1.5b: Complete the table, for the graph of y=f(x) .
- 08M.2.sl.TZ1.5c: Justify your answer to part (b) (ii).
- 10M.1.sl.TZ1.9a: Use the quotient rule to show that f′(x)=−1sin2x .
- 10M.1.sl.TZ1.9c: Find the value of p and of q.
- 10M.1.sl.TZ1.9b: Find f″(x) .
- 10M.1.sl.TZ1.9d: Use information from the table to explain why there is a point of inflexion on the graph of f...
- 09N.1.sl.TZ0.9b: The second derivative f″(x)=40(3x2+4)(x2−4)3 . Use this...
- 09M.1.sl.TZ1.10b: Given that f″(x)=2ax(x2−3)(x2+1)3 , find the coordinates of...
- 09M.1.sl.TZ2.6c: The point P on the graph of f has x-coordinate 3. Explain why P is not a point of inflexion.
- 10N.2.sl.TZ0.7a: There are two points of inflexion on the graph of f . Write down the x-coordinates of these points.
- 10N.2.sl.TZ0.7b: Let g(x)=f″(x) . Explain why the graph of g has no points of inflexion.
- 11M.2.sl.TZ1.9b(i) and (ii): (i) Find f′(x) . (ii) Show that f″(x)=(4x2−2)e−x2 .
- 11M.2.sl.TZ1.9a: Identify the two points of inflexion.
- 11M.2.sl.TZ1.9c: Find the x-coordinate of each point of inflexion.
- 11M.2.sl.TZ1.9d: Use the second derivative to show that one of these points is a point of inflexion.
- 13M.1.sl.TZ1.10c: (i) Find f″(1) . (ii) Hence, show that there is no point of inflexion on the graph...
- 13M.1.sl.TZ2.10b: Explain why P is a point of inflexion.
- 18M.2.sl.TZ1.10b.ii: For the graph of f, write down the period.
- 18M.2.sl.TZ1.10e: Find the first time when the ball’s speed is changing at a rate of 2 cm s−2.
- 18M.2.sl.TZ1.10d: Find the maximum speed of the ball.
- 18M.2.sl.TZ1.10c: Hence, write f(x) in the form pcos(x+r).
- 18M.2.sl.TZ1.10b.i: For the graph of f, write down the amplitude.
- 18M.2.sl.TZ1.10a: Find the coordinates of A.
- 18M.1.sl.TZ1.8c: Find the values of x for which the graph of f is concave-down.
- 18M.1.sl.TZ1.8b: The graph of f has a point of inflexion at x = p. Find p.
- 18M.1.sl.TZ1.8a: Find f (x).