Date | May 2018 | Marks available | 4 | Reference code | 18M.1.sl.TZ1.8 |
Level | SL only | Paper | 1 | Time zone | TZ1 |
Command term | Find | Question number | 8 | Adapted from | N/A |
Question
A function f (x) has derivative f ′(x) = 3x2 + 18x. The graph of f has an x-intercept at x = −1.
Find f (x).
The graph of f has a point of inflexion at x = p. Find p.
Find the values of x for which the graph of f is concave-down.
Markscheme
evidence of integration (M1)
eg ∫f′(x)
correct integration (accept absence of C) (A1)(A1)
eg x3+182x2+C,x3+9x2
attempt to substitute x = −1 into their f = 0 (must have C) M1
eg (−1)3+9(−1)2+C=0,−1+9+C=0
Note: Award M0 if they substitute into original or differentiated function.
correct working (A1)
eg 8+C=0,C=−8
f(x)=x3+9x2−8 A1 N5
[6 marks]
METHOD 1 (using 2nd derivative)
recognizing that f" = 0 (seen anywhere) M1
correct expression for f" (A1)
eg 6x + 18, 6p + 18
correct working (A1)
6p + 18 = 0
p = −3 A1 N3
METHOD 1 (using 1st derivative)
recognizing the vertex of f′ is needed (M2)
eg −b2a (must be clear this is for f′)
correct substitution (A1)
eg −182×3
p = −3 A1 N3
[4 marks]
valid attempt to use f" (x) to determine concavity (M1)
eg f" (x) < 0, f" (−2), f" (−4), 6x + 18 ≤ 0
correct working (A1)
eg 6x + 18 < 0, f" (−2) = 6, f" (−4) = −6
f concave down for x < −3 (do not accept x ≤ −3) A1 N2
[3 marks]