Date | May 2018 | Marks available | 1 | Reference code | 18M.2.sl.TZ1.10 |
Level | SL only | Paper | 2 | Time zone | TZ1 |
Command term | Write down | Question number | 10 | Adapted from | N/A |
Question
Let f(x)=12cosx−5sinx,−π⩽x⩽2π, be a periodic function with f(x)=f(x+2π)
The following diagram shows the graph of f.
There is a maximum point at A. The minimum value of f is −13 .
A ball on a spring is attached to a fixed point O. The ball is then pulled down and released, so that it moves back and forth vertically.
The distance, d centimetres, of the centre of the ball from O at time t seconds, is given by
d(t)=f(t)+17,0⩽t⩽5.
Find the coordinates of A.
For the graph of f, write down the amplitude.
For the graph of f, write down the period.
Hence, write f(x) in the form pcos(x+r).
Find the maximum speed of the ball.
Find the first time when the ball’s speed is changing at a rate of 2 cm s−2.
Markscheme
−0.394791,13
A(−0.395, 13) A1A1 N2
[2 marks]
13 A1 N1
[1 mark]
2π, 6.28 A1 N1
[1 mark]
valid approach (M1)
eg recognizing that amplitude is p or shift is r
f(x)=13cos(x+0.395) (accept p = 13, r = 0.395) A1A1 N3
Note: Accept any value of r of the form 0.395+2πk,k∈Z
[3 marks]
recognizing need for d ′(t) (M1)
eg −12 sin(t) − 5 cos(t)
correct approach (accept any variable for t) (A1)
eg −13 sin(t + 0.395), sketch of d′, (1.18, −13), t = 4.32
maximum speed = 13 (cms−1) A1 N2
[3 marks]
recognizing that acceleration is needed (M1)
eg a(t), d "(t)
correct equation (accept any variable for t) (A1)
eg a(t)=−2,|ddt(d′(t))|=2,−12cos(t)+5sin(t)=−2
valid attempt to solve their equation (M1)
eg sketch, 1.33
1.02154
1.02 A2 N3
[5 marks]