Date | May 2018 | Marks available | 4 | Reference code | 18M.1.sl.TZ1.10 |
Level | SL only | Paper | 1 | Time zone | TZ1 |
Command term | Show that | Question number | 10 | Adapted from | N/A |
Question
The first two terms of an infinite geometric sequence are u1 = 18 and u2 = 12sin2 θ , where 0 < θ < 2ππ , and θ ≠ ππ.
Find an expression for r in terms of θ.
Find the possible values of r.
Show that the sum of the infinite sequence is 542+cos(2θ)542+cos(2θ).
Find the values of θ which give the greatest value of the sum.
Markscheme
valid approach (M1)
eg u2u1,u1u2u2u1,u1u2
r=12sin2θ18(=2sin2θ3)r=12sin2θ18(=2sin2θ3) A1 N2
[2 marks]
recognizing that sinθ is bounded (M1)
eg 0 ≤ sin2 θ ≤ 1, −1 ≤ sinθ ≤ 1, −1 < sinθ < 1
0 < r ≤ 2323 A2 N3
Note: If working shown, award M1A1 for correct values with incorrect inequality sign(s).
If no working shown, award N1 for correct values with incorrect inequality sign(s).
[3 marks]
correct substitution into formula for infinite sum A1
eg 181−2sin2θ3181−2sin2θ3
evidence of choosing an appropriate rule for cos 2θ (seen anywhere) (M1)
eg cos 2θ = 1 − 2 sin2 θ
correct substitution of identity/working (seen anywhere) (A1)
eg 181−23(1−cos2θ2),543−2(1−cos2θ2),183−2sin2θ3181−23(1−cos2θ2),543−2(1−cos2θ2),183−2sin2θ3
correct working that clearly leads to the given answer A1
eg 18×32+(1−2sin2θ),543−(1−cos2θ)18×32+(1−2sin2θ),543−(1−cos2θ)
542+cos(2θ)542+cos(2θ) AG N0
[4 marks]
METHOD 1 (using differentiation)
recognizing dS∞dθ=0dS∞dθ=0 (seen anywhere) (M1)
finding any correct expression for dS∞dθdS∞dθ (A1)
eg 0−54×(−2sin2θ)(2+cos2θ)2,−54(2+cos2θ)−2(−2sin2θ)0−54×(−2sin2θ)(2+cos2θ)2,−54(2+cos2θ)−2(−2sin2θ)
correct working (A1)
eg sin 2θ = 0
any correct value for sin−1(0) (seen anywhere) (A1)
eg 0, ππ, … , sketch of sine curve with x-intercept(s) marked both correct values for 2θ (ignore additional values) (A1)
2θ = ππ, 3ππ (accept values in degrees)
both correct answers θ=π2,3π2θ=π2,3π2 A1 N4
Note: Award A0 if either or both correct answers are given in degrees.
Award A0 if additional values are given.
METHOD 2 (using denominator)
recognizing when S∞ is greatest (M1)
eg 2 + cos 2θ is a minimum, 1−r is smallest
correct working (A1)
eg minimum value of 2 + cos 2θ is 1, minimum r = 2323
correct working (A1)
eg cos2θ=−1,23sin2θ=23,sin2θ=1cos2θ=−1,23sin2θ=23,sin2θ=1
EITHER (using cos 2θ)
any correct value for cos−1(−1) (seen anywhere) (A1)
eg ππ, 3ππ, … (accept values in degrees), sketch of cosine curve with x-intercept(s) marked
both correct values for 2θ (ignore additional values) (A1)
2θ = ππ, 3ππ (accept values in degrees)
OR (using sinθ)
sinθ = ±1 (A1)
sin−1(1) = π2π2 (accept values in degrees) (seen anywhere) A1
THEN
both correct answers θ=π2,3π2θ=π2,3π2 A1 N4
Note: Award A0 if either or both correct answers are given in degrees.
Award A0 if additional values are given.
[6 marks]