Date | May 2010 | Marks available | 1 | Reference code | 10M.2.sl.TZ1.5 |
Level | SL only | Paper | 2 | Time zone | TZ1 |
Command term | Write down | Question number | 5 | Adapted from | N/A |
Question
The graph of y=pcosqx+r , for −5≤x≤14 , is shown below.
There is a minimum point at (0, −3) and a maximum point at (4, 7) .
Find the value of
(i) p ;
(ii) q ;
(iii) r.
The equation y=k has exactly two solutions. Write down the value of k.
Markscheme
(i) evidence of finding the amplitude (M1)
e.g. 7+32 , amplitude =5
p=−5 A1 N2
(ii) period =8 (A1)
q=0.785 (=2π8=π4) A1 N2
(iii) r=7−32 (A1)
r=2 A1 N2
[6 marks]
k=−3 (accept y=−3 ) A1 N1
[1 mark]
Examiners report
Many candidates did not recognize that the value of p was negative. The value of q was often interpreted incorrectly as the period but most candidates could find the value of r, the vertical translation.
In part (b), candidates either could not find a solution or found too many.