Processing math: 100%

User interface language: English | Español

Date November 2017 Marks available 3 Reference code 17N.2.sl.TZ0.10
Level SL only Paper 2 Time zone TZ0
Command term Find Question number 10 Adapted from N/A

Question

Note: In this question, distance is in millimetres.

Let f(x)=x+asin(xπ2)+a, for x0.

The graph of f passes through the origin. Let Pk be any point on the graph of f with x-coordinate 2kπ, where kN. A straight line L passes through all the points Pk.

Diagram 1 shows a saw. The length of the toothed edge is the distance AB.

N17/5/MATME/SP2/ENG/TZ0/10.d_01

The toothed edge of the saw can be modelled using the graph of f and the line L. Diagram 2 represents this model.

N17/5/MATME/SP2/ENG/TZ0/10.d_02

The shaded part on the graph is called a tooth. A tooth is represented by the region enclosed by the graph of f and the line L, between Pk and Pk+1.

Show that f(2π)=2π.

[3]
a.

Find the coordinates of P0 and of P1.

[3]
b.i.

Find the equation of L.

[3]
b.ii.

Show that the distance between the x-coordinates of Pk and Pk+1 is 2π.

[2]
c.

A saw has a toothed edge which is 300 mm long. Find the number of complete teeth on this saw.

[6]
d.

Markscheme

substituting x=2π     M1

eg2π+asin(2ππ2)+a

2π+asin(3π2)+a     (A1)

2πa+a     A1

f(2π)=2π     AG     N0

[3 marks]

a.

substituting the value of k     (M1)

P0(0, 0), P1(2π, 2π)     A1A1     N3

[3 marks]

b.i.

attempt to find the gradient     (M1)

eg2π02π0, m=1

correct working     (A1)

egy2πx2π=1, b=0, y0=1(x0)

y = x     A1     N3

[3 marks]

b.ii.

subtracting x-coordinates of Pk+1 and Pk (in any order)     (M1)

eg2(k+1)π2kπ, 2kπ2kπ2π

correct working (must be in correct order)     A1

eg2kπ+2π2kπ, |2kπ2(k+1)π|

distance is 2π     AG     N0

[2 marks]

c.

METHOD 1

recognizing the toothed-edge as the hypotenuse     (M1)

eg3002=x2+y2, sketch

correct working (using their equation of L     (A1)

eg3002=x2+x2

x=3002 (exact), 212.132     (A1)

dividing their value of x by 2π (do not accept 3002π)     (M1)

eg212.1322π

33.7618     (A1)

33 (teeth)     A1     N2

METHOD 2

vertical distance of a tooth is 2π (may be seen anywhere)     (A1)

attempt to find the hypotenuse for one tooth     (M1)

egx2=(2π)2+(2π)2

x=8π2 (exact), 8.88576     (A1)

dividing 300 by their value of x     (M1)

eg

33.7618     (A1)

33 (teeth)     A1     N2

[6 marks]

d.

Examiners report

[N/A]
a.
[N/A]
b.i.
[N/A]
b.ii.
[N/A]
c.
[N/A]
d.

Syllabus sections

Topic 3 - Circular functions and trigonometry » 3.4 » The circular functions sinx , cosx and tanx : their domains and ranges; amplitude, their periodic nature; and their graphs.
Show 59 related questions

View options