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Date	May 2014	Marks available	3	Reference code	14M.2.sl.TZ1.5
Level	SL only	Paper	2	Time zone	TZ1
Command term	Find	Question number	5	Adapted from	N/A

Question

The population of deer in an enclosed game reserve is modelled by the function \(P(t) = 210\sin (0.5t - 2.6) + 990\), where \(t\) is in months, and \(t = 1\) corresponds to 1 January 2014.

Find the number of deer in the reserve on 1 May 2014.

[3]

Find the rate of change of the deer population on 1 May 2014.

[2]

b(i).

Interpret the answer to part (i) with reference to the deer population size on 1 May 2014.

[1]

b(ii).

Markscheme

\(t = 5\) (A1)

correct substitution into formula (A1)

eg \(210\sin (0.5 \times 5 - 2.6) + 990,{\text{ }}P(5)\)

\(969.034982 \ldots \)

969 (deer) (must be an integer) A1 N3

[3 marks]

evidence of considering derivative (M1)

eg \(P'\)

\(104.475\)

\(104\) (deer per month) A1 N2

[2 marks]

b(i).

(the deer population size is) increasing A1 N1

[1 mark]

b(ii).

Examiners report

[N/A]

b(i).

[N/A]

b(ii).

Syllabus sections

Topic 3 - Circular functions and trigonometry » 3.4 » The circular functions \(\sin x\) , \(\cos x\) and \(\tan x\) : their domains and ranges; amplitude, their periodic nature; and their graphs.

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