Date | May 2014 | Marks available | 2 | Reference code | 14M.2.sl.TZ2.6 |
Level | SL only | Paper | 2 | Time zone | TZ2 |
Command term | Find | Question number | 6 | Adapted from | N/A |
Question
Let f(x)=pcos(q(x+r))+10, for 0⩽. The following diagram shows the graph of f.
The graph has a maximum at (4, 18) and a minimum at (16, 2).
Write down the value of r.
Find p.
Find q.
Solve f(x) = 7.
Markscheme
r = - 4 A2 N2
Note: Award A1 for r = 4.
[2 marks]
evidence of valid approach (M1)
eg \frac{{\max y{\text{ value -- }}y{\text{ value}}}}{2}, distance from y = 10
p = 8 A1 N2
[2 marks]
valid approach (M1)
eg period is 24, \frac{{360}}{{24}}, substitute a point into their f(x)
q = \frac{{2\pi }}{{24}}\left( {\frac{\pi }{{12}},{\text{ exact}}} \right), 0.262 (do not accept degrees) A1 N2
[2 marks]
valid approach (M1)
eg line on graph at y = 7,{\text{ }}8\cos \left( {\frac{{2\pi }}{{24}}(x - 4)} \right) + 10 = 7
x = 11.46828
x = 11.5 (accept (11.5, 7)) A1 N2
[2 marks]
Note: Do not award the final A1 if additional values are given. If an incorrect value of q leads to multiple solutions, award the final A1 only if all solutions within the domain are given.