Date | November 2021 | Marks available | 1 | Reference code | 21N.2.SL.TZ0.5 |
Level | Standard Level | Paper | Paper 2 | Time zone | Time zone 0 |
Command term | Hence and Determine | Question number | 5 | Adapted from | N/A |
Question
The following diagram shows a semicircle with centre O and radius r. Points P, Q and R lie on the circumference of the circle, such that PQ=2r and RˆOQ=θ, where 0<θ<π.
Given that the areas of the two shaded regions are equal, show that θ=2 sin θ.
Hence determine the value of θ.
Markscheme
attempt to find the area of either shaded region in terms of r and θ (M1)
Note: Do not award M1 if they have only copied from the booklet and not applied to the shaded area.
Area of segment =12r2θ-12r2 sin θ A1
Area of triangle =12r2 sin(π-θ) A1
correct equation in terms of θ only (A1)
θ-sin θ=sin(π-θ)
θ-sin θ=sin θ A1
θ=2 sin θ AG
Note: Award a maximum of M1A1A0A0A0 if a candidate uses degrees (i.e., 12r2 sin(180°-θ)), even if later work is correct.
Note: If a candidate directly states that the area of the triangle is 12r2 sin θ, award a maximum of M1A1A0A1A1.
[5 marks]
θ=1.89549…
θ=1.90 A1
Note: Award A0 if there is more than one solution. Award A0 for an answer in degrees.
[1 mark]