Date | May 2021 | Marks available | 1 | Reference code | 21M.2.SL.TZ1.8 |
Level | Standard Level | Paper | Paper 2 | Time zone | Time zone 1 |
Command term | Write down | Question number | 8 | Adapted from | N/A |
Question
Two straight fences meet at point A and a field lies between them.
A horse is tied to a post, P, by a rope of length r metres. Point D is on one fence and point E is on the other, such that PD=PE=PA=r and DˆPE=θ radians. This is shown in the following diagram.
The length of the arc DE shown in the diagram is 28 m.
A new fence is to be constructed between points B and C which will enclose the field, as shown in the following diagram.
Point C is due west of B and AC=800 m . The bearing of B from A is 195°.
Write down an expression for in terms of .
Show that the area of the field that the horse can reach is .
The area of field that the horse can reach is . Find the value of .
Hence, find the size of .
Find the size of .
Find the length of new fence required.
Markscheme
A1
[1 mark]
recognising sum of area of sector and area of triangle required (M1)
A1
(substitution seen anywhere) A1
OR A1
area AG
[4 marks]
(M1)
A1
[2 marks]
OR (M1)
A1
[2 marks]
(A1)
A1
[2 marks]
choosing sine rule (M1)
OR A1
A1
[2 marks]