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Date May 2019 Marks available 3 Reference code 19M.1.SL.TZ1.S_3
Level Standard Level Paper Paper 1 (without calculator) Time zone Time zone 1
Command term Find Question number S_3 Adapted from N/A

Question

The following diagram shows a right triangle ABC. Point D lies on AB such that CD bisects AĈB.

AĈD = θ and AC = 14 cm

Given that  sin θ = 3 5 , find the value of  cos θ .

[3]
a.

Find the value of  cos 2 θ .

[3]
b.

Hence or otherwise, find BC .

[2]
c.

Markscheme

valid approach       (M1)

eg      labelled sides on separate triangle,  si n 2 x + co s 2 x = 1

correct working       (A1)

eg      missing side is 4,  1 ( 3 5 ) 2

cos θ = 4 5                           A1   N3

[3 marks]

a.

correct substitution into  cos 2 θ        (A1)

eg      2 ( 16 25 ) 1 ,   1 2 ( 3 5 ) 2 ,   16 25 9 25

cos 2 θ = 7 25                          A1   N2

[2 marks]

b.

correct working      (A1)

eg      7 25 = 14 BC BC = 14 × 25 7

BC = 50  (cm)                        A1   N2

[2 marks]

c.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.

Syllabus sections

Topic 3— Geometry and trigonometry » SL 3.2—2d and 3d trig, sine rule, cosine rule, area
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Topic 3— Geometry and trigonometry

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