Date | May 2021 | Marks available | 7 | Reference code | 21M.1.SL.TZ2.6 |
Level | Standard Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 2 |
Command term | Find | Question number | 6 | Adapted from | N/A |
Question
The following diagram shows triangle ABCABC, with AB=10AB=10, BC=xBC=x and AC=2xAC=2x.
Given that cos ˆC=34cosˆC=34, find the area of the triangle.
Give your answer in the form p√q2p√q2 where p, q∈ℤ+.
Markscheme
METHOD 1
attempt to use the cosine rule to find the value of x (M1)
100=x2+4x2-2(x)(2x)(34) A1
2x2=100
x2=50 OR x=√50 (=5√2) A1
attempt to find sin ˆC (seen anywhere) (M1)
sin2 ˆC+(34)2=1 OR x2+32=42 or right triangle with side 3 and hypotenuse 4
sin ˆC=√74 (A1)
Note: The marks for finding sin ˆC may be awarded independently of the first three marks for finding x.
correct substitution into the area formula using their value of x (or x2) and their value of sin ˆC (M1)
A=12×5√2×10√2×√74 or A=12×√50×2√50×√74
A=25√72 A1
METHOD 2
attempt to find the height, h, of the triangle in terms of x (M1)
h2+(34x)2=x2 OR h2+(54x)2=102 OR h=√74x A1
equating their expressions for either h2 or h (M1)
x2-(34x)2=102-(54x)2 OR √100-2516x2=√74x (or equivalent) A1
x2=50 OR x=√50 (=5√2) A1
correct substitution into the area formula using their value of x (or x2) (M1)
A=12×2√50×√74√50 OR A=12(2×5√2)(√745√2)
A=25√72 A1
[7 marks]