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Date November 2019 Marks available 6 Reference code 19N.2.SL.TZ0.S_6
Level Standard Level Paper Paper 2 Time zone Time zone 0
Command term Calculate Question number S_6 Adapted from N/A

Question

The diagram below shows a triangular-based pyramid with base  ADC .
Edge  BD is perpendicular to the edges  AD and  CD .

AC = 28.4 cm ,   AB = x cm ,   BC = x + 2 cm ,   A B ^ C = 0.667 ,   B A ^ D = 0.611

Calculate  AD

Markscheme

evidence of choosing cosine rule        (M1)

eg        a 2 = b 2 + c 2 2 b c cos A

correct substitution to find  AB         (A1)

eg        28.4 2 = x 2 + ( x + 2 ) 2 2 x ( x + 2 ) cos ( 0.667 )

x = 42.2822        A2

appropriate approach to find  AD         (M1)

eg        AD = x cos ( 0.611 ) ,   cos ( 0.611 ) = AD 42.2822

34.6322

AD = 34.6        A1  N3

[6 marks]

Examiners report

[N/A]

Syllabus sections

Topic 3— Geometry and trigonometry » SL 3.2—2d and 3d trig, sine rule, cosine rule, area
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Topic 3— Geometry and trigonometry

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