Date | May 2021 | Marks available | 5 | Reference code | 21M.1.AHL.TZ2.8 |
Level | Additional Higher Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 2 |
Command term | Find | Question number | 8 | Adapted from | N/A |
Question
The lines l1 and l2 have the following vector equations where λ, μ∈ℝ.
l1:r1=(32-1)+λ(2-22)
l2:r2=(204)+μ(1-11)
Show that l1 and l2 do not intersect.
Find the minimum distance between l1 and l2.
Markscheme
METHOD 1
setting at least two components of l1 and l2 equal M1
3+2λ=2+μ (1)
2-2λ=-μ (2)
-1+2λ=4+μ
attempt to solve two of the equations eg. adding and M1
gives a contradiction (no solution), eg R1
so and do not intersect AG
Note: For an error within the equations award M0M1R0.
Note: The contradiction must be correct to award the R1.
METHOD 2
and are parallel, so and are either identical or distinct. R1
Attempt to subtract two position vectors from each line,
e.g. M1
A1
[3 marks]
METHOD 1
and are parallel (as is a multiple of )
let be on and let be on
Attempt to find vector (M1)
Distance required is M1
(A1)
A1
minimum distance is A1
METHOD 2
and are parallel (as is a multiple of )
let be a fixed point on eg and let be a general point on
attempt to find vector (M1)
A1
M1
EITHER
null A1
OR
to obtain A1
THEN
minimum distance is A1
METHOD 3
let be on and let be on (M1)
(or let be on and let be on )
(or ) A1
(or ) M1
or A1
minimum distance is A1
[5 marks]