Date | May 2017 | Marks available | 4 | Reference code | 17M.1.SL.TZ2.S_2 |
Level | Standard Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 2 |
Command term | Find | Question number | S_2 | Adapted from | N/A |
Question
The vectors a = (42)(42) and b = (k+3k) are perpendicular to each other.
Find the value of k.
Given that c = a + 2b, find c.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
evidence of scalar product M1
ega ∙ b, 4(k+3)+2k
recognizing scalar product must be zero (M1)
ega ∙ b =0, 4k+12+2k=0
correct working (must involve combining terms) (A1)
eg 6k+12,6k=−12
k=−2 A1 N2
[4 marks]
attempt to substitute their value of k (seen anywhere) (M1)
egb = (−2+3−2), 2b = (2−4)
correct working (A1)
eg(42)+(2−4), (4+2k+62+2k)
c = (6−2) A1 N2
[3 marks]