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Date May 2019 Marks available 4 Reference code 19M.1.AHL.TZ1.H_1
Level Additional Higher Level Paper Paper 1 (without calculator) Time zone Time zone 1
Command term Find Question number H_1 Adapted from N/A

Question

Let a = (2k1)2k1 and b = (3k+2k)3k+2k, kR.

Given that a and b are perpendicular, find the possible values of k.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

a b = (2k1)(3k+2k)

=6+k(k+2)k      A1

a b = 0        (M1)

k2+k6=0

attempt at solving their quadratic equation        (M1)

(k+3)(k2)=0

k=3,2      A1

Note: Attempt at solving using |a||b| = |a × b| will be M1A0A0A0 if neither answer found M1(A1)A1A0
for one correct answer and M1(A1)A1A1 for two correct answers.

[4 marks]

Examiners report

[N/A]

Syllabus sections

Topic 3— Geometry and trigonometry » AHL 3.13—Scalar (dot) product
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Topic 3— Geometry and trigonometry

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