Date | May 2019 | Marks available | 4 | Reference code | 19M.1.AHL.TZ1.H_1 |
Level | Additional Higher Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 1 |
Command term | Find | Question number | H_1 | Adapted from | N/A |
Question
Let a = (2k−1)⎛⎜⎝2k−1⎞⎟⎠ and b = (−3k+2k)⎛⎜⎝−3k+2k⎞⎟⎠, k∈R.
Given that a and b are perpendicular, find the possible values of k.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
a • b = (2k−1)∙(−3k+2k)
=−6+k(k+2)−k A1
a • b = 0 (M1)
k2+k−6=0
attempt at solving their quadratic equation (M1)
(k+3)(k−2)=0
k=−3,2 A1
Note: Attempt at solving using |a||b| = |a × b| will be M1A0A0A0 if neither answer found M1(A1)A1A0
for one correct answer and M1(A1)A1A1 for two correct answers.
[4 marks]