Date | May 2018 | Marks available | 6 | Reference code | 18M.1.SL.TZ1.S_6 |
Level | Standard Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 1 |
Command term | Find | Question number | S_6 | Adapted from | N/A |
Question
Six equilateral triangles, each with side length 3 cm, are arranged to form a hexagon.
This is shown in the following diagram.
The vectors p , q and r are shown on the diagram.
Find p•(p + q + r).
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
METHOD 1 (using |p| |2q| cosθ)
finding p + q + r (A1)
eg 2q,
| p + q + r | = 2 × 3 (= 6) (seen anywhere) A1
correct angle between p and q (seen anywhere) (A1)
(accept 60°)
substitution of their values (M1)
eg 3 × 6 × cos
correct value for cos (seen anywhere) (A1)
eg
p•(p + q + r) = 9 A1 N3
METHOD 2 (scalar product using distributive law)
correct expression for scalar distribution (A1)
eg p• p + p•q + p•r
three correct angles between the vector pairs (seen anywhere) (A2)
eg 0° between p and p, between p and q, between p and r
Note: Award A1 for only two correct angles.
substitution of their values (M1)
eg 3.3.cos0 +3.3.cos + 3.3.cos120
one correct value for cos0, cos or cos (seen anywhere) A1
eg
p•(p + q + r) = 9 A1 N3
METHOD 3 (scalar product using relative position vectors)
valid attempt to find one component of p or r (M1)
eg sin 60 = , cos 60 = , one correct value
one correct vector (two or three dimensions) (seen anywhere) A1
eg
three correct vectors p + q + r = 2q (A1)
p + q + r = or (seen anywhere, including scalar product) (A1)
correct working (A1)
eg
p•(p + q + r) = 9 A1 N3
[6 marks]