Date | May 2021 | Marks available | 8 | Reference code | 21M.1.AHL.TZ1.11 |
Level | Additional Higher Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 1 |
Command term | Find | Question number | 11 | Adapted from | N/A |
Question
Consider the line L1L1 defined by the Cartesian equation x+12=y=3-z.
Consider a second line L2 defined by the vector equation r=(012)+t(a1-1), where t∈ℝ and a∈ℝ.
Show that the point (-1, 0, 3) lies on L1.
Find a vector equation of L1.
Find the possible values of a when the acute angle between L1 and L2 is 45°.
It is given that the lines L1 and L2 have a unique point of intersection, A, when a≠k.
Find the value of k, and find the coordinates of the point A in terms of a.
Markscheme
-1+12=0=3-3 A1
the point (-1, 0, 3) lies on L1. AG
[1 mark]
attempt to set equal to a parameter or rearrange cartesian form (M1)
x+12=y=3-z=λ⇒x=2λ-1, y=λ, z=3-λ OR x+12=y-01=z-3-1
correct direction vector (21-1) or equivalent seen in vector form (A1)
r=(-103)+λ(21-1) (or equivalent) A1
Note: Award A0 if =r is omitted.
[3 marks]
attempt to use the scalar product formula (M1)
(21-1)∙(a1-1)=(±)√6√a2+2 cos 45° (A1)(A1)
Note: Award A1 for LHS and A1 for RHS
2a+2=(±)√6√a2+2√22(⇒2a+2=(±)√3√a2+2) A1A1
Note: Award A1 for LHS and A1 for RHS
4a2+8a+4=3a2+6 A1
a2+8a-2=0 M1
attempt to solve their quadratic
a=-8±√64+82=-8±√722(=-4±3√2) A1
[8 marks]
METHOD 1
attempt to equate the parametric forms of L1 and L2 (M1)
{2λ-1=taλ=1+t3-λ=2-t A1
attempt to solve equations by eliminating λ or t (M1)
2+2t-1=ta⇒1=t(a-2) or 2λ-1=(λ-1)a⇒a-1=λ(a-2)
Solutions exist unless a-2=0
k=2 A1
Note: This A1 is independent of the following marks.
t=1a-2 or λ=a-1a-2 A1
A has coordinates (aa-2, 1+1a-2, 2-1a-2) (=(aa-2, a-1a-2, 2a-5a-2)) A2
Note: Award A1 for any two correct coordinates seen or final answer in vector form.
METHOD 2
no unique point of intersection implies direction vectors of L1 and L2 parallel
k=2 A1
Note: This A1 is independent of the following marks.
attempt to equate the parametric forms of L1 and L2 (M1)
{2λ-1=taλ=1+t3-λ=2-t A1
attempt to solve equations by eliminating λ or t (M1)
2+2t-1=ta⇒1=t(a-2) or 2λ-1=(λ-1)a⇒a-1=λ(a-2)
t=1a-2 or λ=a-1a-2 A1
A has coordinates (aa-2, 1+1a-2, 2-1a-2) (=(aa-2, a-1a-2, 2a-5a-2)) A2
Note: Award A1 for any two correct coordinates seen or final answer in vector form.
[7 marks]