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Date	May 2017	Marks available	5	Reference code	17M.1.SL.TZ2.S_9
Level	Standard Level	Paper	Paper 1 (without calculator)	Time zone	Time zone 2
Command term	Find	Question number	S_9	Adapted from	N/A

Question

Note: In this question, distance is in metres and time is in seconds.

Two particles $P_{1}$ ${P_1}$ and $P_{2}$ ${P_2}$ start moving from a point A at the same time, along different straight lines.

After $t$ $t$ seconds, the position of $P_{1}$ ${P_1}$ is given by r = $⎛ ⎜ ⎝ \begin{matrix} 4 - 1 3 \end{matrix} ⎞ ⎟ ⎠ + t ⎛ ⎜ ⎝ \begin{matrix} 12 - 1 \end{matrix} ⎞ ⎟ ⎠$ $\left( {\begin{array}{*{20}{c}} 4 \\ { - 1} \\ 3 \end{array}} \right) + t\left( {\begin{array}{*{20}{c}} 1 \\ 2 \\ { - 1} \end{array}} \right)$ .

Two seconds after leaving A, $P_{1}$ ${P_1}$ is at point B.

Two seconds after leaving A, $P_{2}$ ${P_2}$ is at point C, where $- - \to AC = ⎛ ⎜ ⎝ \begin{matrix} 304 \end{matrix} ⎞ ⎟ ⎠$ $\overrightarrow {{\text{AC}}} = \left( {\begin{array}{*{20}{c}} 3 \\ 0 \\ 4 \end{array}} \right)$ .

Find the coordinates of A.

[2]

Find $- - \to AB$ $\overrightarrow {{\text{AB}}}$ ;

[3]

b.i.

Find $∣ ∣ ∣ - - \to AB ∣ ∣ ∣$ $\left| {\overrightarrow {{\text{AB}}} } \right|$ .

[2]

b.ii.

Find $cos B^A C$ $\cos {\rm{B\hat AC}}$ .

[5]

Hence or otherwise, find the distance between $P_{1}$ ${P_1}$ and $P_{2}$ ${P_2}$ two seconds after they leave A.

[4]

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

recognizing $t = 0$ $t = 0$ at A (M1)

A is $(4, - 1, 3)$ $(4,{\text{ }} - 1,{\text{ }}3)$ A1 N2

[2 marks]

METHOD 1

valid approach (M1)

eg $\,\,\,\,\,$ $⎛ ⎜ ⎝ \begin{matrix} 4 - 1 3 \end{matrix} ⎞ ⎟ ⎠ + 2 ⎛ ⎜ ⎝ \begin{matrix} 12 - 2 \end{matrix} ⎞ ⎟ ⎠, (6, 3, - 1)$ $\left( {\begin{array}{*{20}{c}} 4 \\ { - 1} \\ 3 \end{array}} \right) + 2\left( {\begin{array}{*{20}{c}} 1 \\ 2 \\ { - 2} \end{array}} \right),{\text{ }}(6,{\text{ }}3,{\text{ }} - 1)$

correct approach to find $- - \to AB$ $\overrightarrow {{\text{AB}}}$ (A1)

eg $\,\,\,\,\,$ $AO + OB, B - A, ⎛ ⎜ ⎝ \begin{matrix} 63 - 1 \end{matrix} ⎞ ⎟ ⎠ - ⎛ ⎜ ⎝ \begin{matrix} 4 - 1 3 \end{matrix} ⎞ ⎟ ⎠$ ${\text{AO}} + {\text{OB}},{\text{ B}} - {\text{A, }}\left( {\begin{array}{*{20}{c}} 6 \\ 3 \\ { - 1} \end{array}} \right) - \left( {\begin{array}{*{20}{c}} 4 \\ { - 1} \\ 3 \end{array}} \right)$

$- - \to AB = ⎛ ⎜ ⎝ \begin{matrix} 24 - 4 \end{matrix} ⎞ ⎟ ⎠$ $\overrightarrow {{\text{AB}}} = \left( {\begin{array}{*{20}{c}} 2 \\ 4 \\ { - 4} \end{array}} \right)$ A1 N2

METHOD 2

recognizing $- - \to AB$ $\overrightarrow {{\text{AB}}}$ is two times the direction vector (M1)

correct working (A1)

eg $\,\,\,\,\,$ $- - \to AB = 2 ⎛ ⎜ ⎝ \begin{matrix} 12 - 2 \end{matrix} ⎞ ⎟ ⎠$ $\overrightarrow {{\text{AB}}} = 2\left( {\begin{array}{*{20}{c}} 1 \\ 2 \\ { - 2} \end{array}} \right)$

$- - \to AB = ⎛ ⎜ ⎝ \begin{matrix} 24 - 4 \end{matrix} ⎞ ⎟ ⎠$ $\overrightarrow {{\text{AB}}} = \left( {\begin{array}{*{20}{c}} 2 \\ 4 \\ { - 4} \end{array}} \right)$ A1 N2

[3 marks]

b.i.

correct substitution (A1)

eg $\,\,\,\,\,$ $∣ ∣ ∣ - - \to AB ∣ ∣ ∣ = \sqrt{2^{2} + 4^{2} + 4^{2}}, \sqrt{4 + 16 + 16}, \sqrt{36}$ $\left| {\overrightarrow {{\text{AB}}} } \right| = \sqrt {{2^2} + {4^2} + {4^2}} ,{\text{ }}\sqrt {4 + 16 + 16} ,{\text{ }}\sqrt {36}$

$∣ ∣ ∣ - - \to AB ∣ ∣ ∣ = 6$ $\left| {\overrightarrow {{\text{AB}}} } \right| = 6$ A1 N2

[2 marks]

b.ii.

METHOD 1 (vector approach)

valid approach involving $- - \to AB$ $\overrightarrow {{\text{AB}}}$ and $- - \to AC$ $\overrightarrow {{\text{AC}}}$ (M1)

eg $\,\,\,\,\,$ $- - \to AB ∙ - - \to AC, \frac{- - \to BA ∙ - - \to AC}{AB \times AC}$ $\overrightarrow {{\text{AB}}} \bullet \overrightarrow {{\text{AC}}} ,{\text{ }}\frac{{\overrightarrow {{\text{BA}}} \bullet \overrightarrow {{\text{AC}}} }}{{{\text{AB}} \times {\text{AC}}}}$

finding scalar product and $∣ ∣ ∣ - - \to AC ∣ ∣ ∣$ $\left| {\overrightarrow {{\text{AC}}} } \right|$ (A1)(A1)

scalar product $2 (3) + 4 (0) - 4 (4) (= - 10)$ $2(3) + 4(0) - 4(4){\text{ }}( = - 10)$

$∣ ∣ ∣ - - \to AC ∣ ∣ ∣ = \sqrt{3^{2} + 0^{2} + 4^{2}} (= 5)$ $\left| {\overrightarrow {{\text{AC}}} } \right| = \sqrt {{3^2} + {0^2} + {4^2}} {\text{ }}( = 5)$

substitution of their scalar product and magnitudes into cosine formula (M1)

eg $\,\,\,\,\,$ $cos B^A C = \frac{6 + 0 - 16}{6 \sqrt{3^{2} + 4^{2}}}$ $\cos {\rm{B\hat AC = }}\frac{{6 + 0 - 16}}{{6\sqrt {{3^2} + {4^2}} }}$

$cos B^A C = - \frac{10}{30} (= - \frac{1}{3})$ ${\text{cos}}\,B\hat AC = - \frac{{10}}{{30}}\left( { = - \frac{1}{3}} \right)$ A1 N2

METHOD 2 (triangle approach)

valid approach involving cosine rule (M1)

eg $\,\,\,\,\,$ $cos B^A C = \frac{A B^{2} + A C^{2} - B C^{2}}{2 \times AB \times AC}$ $\cos {\rm{B\hat AC = }}\frac{{{\text{A}}{{\text{B}}^2} + {\text{A}}{{\text{C}}^2} - {\text{B}}{{\text{C}}^2}}}{{2 \times {\text{AB}} \times {\text{AC}}}}$

finding lengths AC and BC (A1)(A1)

$AC = 5, BC = 9$ ${\text{AC}} = 5,{\text{ BC}} = 9$

substitution of their lengths into cosine formula (M1)

eg $\,\,\,\,\,$ $cos B^A C = \frac{5^{2} + 6^{2} - 9^{2}}{2 \times 5 \times 6}$ $\cos {\rm{B\hat AC}} = \frac{{{5^2} + {6^2} - {9^2}}}{{2 \times 5 \times 6}}$

$cos B^A C = - \frac{20}{60} (= - \frac{1}{3})$ $\cos {\rm{B\hat AC}} = - \frac{{20}}{{60}}{\text{ }}\left( { = - \frac{1}{3}} \right)$ A1 N2

[5 marks]

Note: Award relevant marks for working seen to find BC in part (c) (if cosine rule used in part (c)).

METHOD 1 (using cosine rule)

recognizing need to find BC (M1)

choosing cosine rule (M1)

eg $\,\,\,\,\,$ $c^{2} = a^{2} + b^{2} - 2 a b cos C$ ${c^2} = {a^2} + {b^2} - 2ab\cos {\text{C}}$

correct substitution into RHS A1

eg $\,\,\,\,\,$ $B C^{2} = (6)^{2} + (5)^{2} - 2 (6) (5) (- \frac{1}{3}), 36 + 25 + 20$ ${\text{B}}{{\text{C}}^2} = {(6)^2} + {(5)^2} - 2(6)(5)\left( { - \frac{1}{3}} \right),{\text{ }}36 + 25 + 20$

distance is 9 A1 N2

METHOD 2 (finding magnitude of $- - \to B C$ $\overrightarrow {BC}$ )

recognizing need to find BC (M1)

valid approach (M1)

eg $\,\,\,\,\,$ attempt to find $- - \to O B$ $\overrightarrow {{\rm{OB}}}$ or $- - \to O C$ $\overrightarrow {{\rm{OC}}}$ , $- - \to O B = ⎛ ⎜ ⎝ \begin{matrix} 63 - 1 \end{matrix} ⎞ ⎟ ⎠$ $\overrightarrow {{\rm{OB}}} = \left( {\begin{array}{*{20}{c}} 6 \\ 3 \\ { - 1} \end{array}} \right)$ or $- - \to O C = ⎛ ⎜ ⎝ \begin{matrix} 7 - 1 7 \end{matrix} ⎞ ⎟ ⎠, - - \to B A + - - \to A C$ $\overrightarrow {{\rm{OC}}} = \left( {\begin{array}{*{20}{c}} 7 \\ { - 1} \\ 7 \end{array}} \right),{\text{ }}\overrightarrow {{\rm{BA}}} + \overrightarrow {{\rm{AC}}}$

correct working A1

eg $\,\,\,\,\,$ $- - \to B C = ⎛ ⎜ ⎝ \begin{matrix} 1 - 4 8 \end{matrix} ⎞ ⎟ ⎠, - - \to C B = ⎛ ⎜ ⎝ \begin{matrix} - 1 4 - 8 \end{matrix} ⎞ ⎟ ⎠, \sqrt{1^{2} + 4^{2} + 8^{2}} = \sqrt{81}$ $\overrightarrow {{\rm{BC}}} = \left( {\begin{array}{*{20}{c}} 1 \\ { - 4} \\ 8 \end{array}} \right),{\text{ }}\overrightarrow {{\rm{CB}}} = \left( {\begin{array}{*{20}{c}} { - 1} \\ 4 \\ { - 8} \end{array}} \right),{\text{ }}\sqrt {{1^2} + {4^2} + {8^2}} = \sqrt {81}$

distance is 9 A1 N2

METHOD 3 (finding coordinates and using distance formula)

recognizing need to find BC (M1)

valid approach (M1)

eg $\,\,\,\,\,$ attempt to find coordinates of B or C, $B (6, 3, - 1)$ ${\text{B}}(6,{\text{ }}3,{\text{ }} - 1)$ or $C (7, - 1, 7)$ ${\text{C}}(7,{\text{ }} - 1,{\text{ }}7)$

correct substitution into distance formula A1

eg $\,\,\,\,\,$ $BC = \sqrt{{(6 - 7)}^{2} + {(3 - (- 1))}^{2} + {(- 1 - 7)}^{2}}, \sqrt{1^{2} + 4^{2} + 8^{2}} = \sqrt{81}$ ${\text{BC}} = \sqrt {{{(6 - 7)}^2} + {{\left( {3 - ( - 1)} \right)}^2} + {{( - 1 - 7)}^2}} ,{\text{ }}\sqrt {{1^2} + {4^2} + {8^2}} = \sqrt {81}$

distance is 9 A1 N2

[4 marks]

Examiners report

[N/A]

b.i.

[N/A]

b.ii.

[N/A]

Syllabus sections

Topic 3— Geometry and trigonometry » AHL 3.14—Vector equation of line

Show 98 related questions

22M.1.AHL.TZ1.11b.i:
Verify that the point $P (1, - 2, 0)$ $P (1, - 2, 0)$ lies on both $\prod_{1}$ $\prod_{1}$ and $\prod_{2}$ $\prod_{2}$ .
17M.1.SL.TZ2.S_9d:
Hence or otherwise, find the distance between $P_{1}$ ${P_1}$ and $P_{2}$ ${P_2}$ two seconds after they leave A.
18M.1.SL.TZ1.S_9d:
Point D is also on L and has coordinates (8, 4, −9).

Find the area of triangle OCD.
17M.1.SL.TZ1.S_8d.ii:
Hence or otherwise, find one point on $L_{2}$ ${L_2}$ which is $\sqrt{5}$ $\sqrt 5$ units from C.
18M.1.AHL.TZ2.H_9a.i:
Explain why ABCD is a parallelogram.
18M.1.AHL.TZ2.H_9e:
Find the Cartesian equation of $Π$ $\Pi$ .
19M.1.AHL.TZ1.H_11d:
Write down $- - \to PA$ $\overrightarrow {{\text{PA}}}$ and $- \to PB$ $\overrightarrow {{\text{PB}}}$ .
17M.2.AHL.TZ2.H_9f:
Find a vector perpendicular to the plane Π $_{3}$ $_3$ .
19M.1.AHL.TZ1.H_11a.i:
Find how many sets of four points can be selected which can form the vertices of a quadrilateral.
17M.2.AHL.TZ2.H_9a:
Find the vector equation of the line (BC).
19N.2.SL.TZ0.S_2b:
Write down a direction vector for $L_{3}$ ${L_3}$ .
19M.1.AHL.TZ1.H_11c:
Write down the value of $λ$ $\lambda$ corresponding to the point $A$ ${\text{A}}$ .
19N.1.AHL.TZ0.H_8:
A straight line, $L_{θ}$ ${L_\theta }$ , has vector equation r $= \left( {\begin{array}{*{20}{c}} 5 \\ 0 \\ 0 \end{array}} \right) + \lambda \left( {\begin{array}{*{20}{c}} 5 \\ {{\text{sin}}\,\theta } \\ {{\text{cos}}\,\theta } \end{array}} \right){\text{, }}\lambda {\text{, }}\theta \in \mathbb{R}$ .

The plane ${\Pi _p}$ , has equation $x = p{\text{, }}p \in \mathbb{R}$ .

Show that the angle between ${L_\theta }$ and ${\Pi _p}$ is independent of both $\theta$ and $p$ .
19M.1.AHL.TZ1.H_11a.ii:
Find how many sets of three points can be selected which can form the vertices of a triangle.
17M.1.SL.TZ2.S_9a:
Find the coordinates of A.
18M.1.AHL.TZ2.H_9d:
Find the vector equation of the straight line passing through M and normal to the plane $\Pi$ containing ABCD.
17M.1.SL.TZ1.S_8d.i:
Find a unit vector in the direction of ${L_2}$ .
17M.2.AHL.TZ2.H_9d:
Show that the line (BC) lies in the plane Π $_1$ .
16N.1.SL.TZ0.S_4a:
Find a vector equation of the line that passes through P and Q.
18N.2.SL.TZ0.S_8d:
Find the area of triangle ABC.
17N.1.SL.TZ0.S_9a.i:
Show that $\overrightarrow {{\text{AB}}} = \left( {\begin{array}{*{20}{c}} 2 \\ { - 1} \\ 1 \end{array}} \right)$ .
16N.1.SL.TZ0.S_4b:
The line through P and Q is perpendicular to the vector 2i $+$ nk. Find the value of $n$ .
17N.1.SL.TZ0.S_9b:
Find the value of $p$ .
18M.1.SL.TZ2.S_1a:
Find a vector equation for L₁.
16N.1.AHL.TZ0.H_8a:
find the value of $a$ ;
22M.1.AHL.TZ1.11b.ii:
Find a vector equation of $L$ , the line of intersection of $\prod_{1}$ and $\prod_{2}$ .
22M.1.AHL.TZ1.11c:
Find the distance between $L$ and $\prod_{3}$ .
18N.2.SL.TZ0.S_8b.ii:
Show that $\overrightarrow {{\text{AC}}} = \left( {\begin{array}{*{20}{c}} 8 \\ { - 10} \\ { - 1} \end{array}} \right)$ .
22M.2.AHL.TZ2.11b:
Show that airplane $A$ travels at a greater speed than airplane $B$ .
18M.1.SL.TZ1.S_9b.i:
Find a vector equation for L.
17M.1.SL.TZ1.S_8a.ii:
Hence, write down a vector equation for ${L_1}$ .
EXN.2.AHL.TZ0.11d.ii:
Hence determine the minimum distance, $d_{min}$ , from $D$ to $Π$ .
19M.1.SL.TZ1.S_2b:
A second line, ${L_2}$ , is parallel to ${L_1}$ and passes through (1, 2, 3).

Write down a vector equation for ${L_2}$ .
18N.1.AHL.TZ0.H_9b:
Find, in terms of $b$ , the equation of the line L which passes through M and is perpendicular to the plane П.
19M.2.SL.TZ2.S_7:
The vector equation of line $L$ is given by r $= \left( {\begin{array}{*{20}{c}} { - 1} \\ 3 \\ 8 \end{array}} \right) + t\left( {\begin{array}{*{20}{c}} 4 \\ 5 \\ { - 1} \end{array}} \right)$ .

Point P is the point on $L$ that is closest to the origin. Find the coordinates of P.
21M.1.AHL.TZ1.11a.i:
Show that the point $(- 1, 0, 3)$ lies on $L_{1}$ .
21M.1.AHL.TZ1.11b:
Find the possible values of $a$ when the acute angle between $L_{1}$ and $L_{2}$ is $45 °$ .
18N.2.SL.TZ0.S_8a.i:
Find $\overrightarrow {{\text{AB}}}$ .
17M.2.AHL.TZ2.H_9c:
Find the Cartesian equation of the plane Π $_1$ , which passes through C and is perpendicular to $\overrightarrow {{\rm{OA}}}$ .
18M.1.AHL.TZ2.H_9a.ii:
Using vector algebra, show that $\mathop {{\text{AD}}}\limits^ \to = \mathop {{\text{BC}}}\limits^ \to$ .
20N.1.SL.TZ0.S_7b:
Particle $P_{2}$ also moves in a straight line. The position of $P_{2}$ is given by $r = (\begin{matrix} - 1 \\ 6 \end{matrix}) + t (\begin{matrix} 4 \\ - 3 \end{matrix})$ .

The speed of $P_{1}$ is greater than the speed of $P_{2}$ when $t > q$ .

Find the value of $q$ .
20N.1.SL.TZ0.S_9b:
Find the value of $m$ .
18N.2.SL.TZ0.S_8a.ii:
Find $\left| {\overrightarrow {{\text{AB}}} } \right|$ .
19N.2.SL.TZ0.S_2c:
${L_3}$ passes through the intersection of ${L_1}$ and ${L_2}$ .

Write down a vector equation for ${L_3}$ .
18N.2.SL.TZ0.S_8c:
Find the angle between $\overrightarrow {{\text{AB}}}$ and $\overrightarrow {{\text{AC}}}$ .
SPM.1.AHL.TZ0.8:
The plane П has the Cartesian equation $2x + y + 2z = 3$

The line L has the vector equation r $= \left( {\begin{array}{*{20}{c}} 3 \\ { - 5} \\ 1 \end{array}} \right) + \mu \left( {\begin{array}{*{20}{c}} 1 \\ { - 2} \\ p \end{array}} \right){\text{,}}\,\,\mu {\text{,}}\,p \in \mathbb{R}$ . The acute angle between the line L and the plane П is 30°.

Find the possible values of $p$ .
16N.1.AHL.TZ0.H_8b:
determine the coordinates of the point of intersection P.
17M.2.AHL.TZ2.H_9b:
Determine whether or not the lines (OA) and (BC) intersect.
19M.2.SL.TZ1.S_9a:
Find the gradient of $L$ .
18M.1.AHL.TZ2.H_9b:
Show that p = 1, q = 1 and r = 4.
19M.1.AHL.TZ1.H_11e:
Let ${\text{C}}$ be the point on ${l_1}$ with coordinates (1, 0, 1) and ${\text{D}}$ be the point on ${l_2}$ with parameter $\mu = - 2$ .

Find the area of the quadrilateral ${\text{CDBA}}$ .
17M.1.SL.TZ2.S_9b.i:
Find $\overrightarrow {{\text{AB}}}$ ;
EXN.2.AHL.TZ0.11a:
Find the vectors $\vec{AB}$ and $\vec{AC}$ .
17N.1.SL.TZ0.S_9a.ii:
Find a vector equation for $L$ .
EXN.2.AHL.TZ0.11b:
Use a vector method to show that $B \hat{A} C = 60 °$ .
17M.1.SL.TZ1.S_8a.i:
Find $\overrightarrow {AB}$ .
21M.1.AHL.TZ1.11a.ii:
Find a vector equation of $L_{1}$ .
18M.1.SL.TZ1.S_9a:
Show that $\mathop {{\text{AB}}}\limits^ \to = \left( \begin{gathered} \,6 \hfill \\ \,8 \hfill \\ - 5 \hfill \\ \end{gathered} \right)$
18N.2.SL.TZ0.S_8b.i:
Find the value of $y$ .
17N.1.AHL.TZ0.H_2b:
Find the coordinates of the point of intersection of the line L with the plane Π.
19N.2.SL.TZ0.S_2a:
Find the point of intersection of ${L_1}$ and ${L_2}$ .
17N.1.SL.TZ0.S_9c:
The point D has coordinates $({q^2},{\text{ }}0,{\text{ }}q)$ . Given that $\overrightarrow {{\text{DC}}}$ is perpendicular to $L$ , find the possible values of $q$ .
22M.1.AHL.TZ1.11a:
Show that the three planes do not intersect.
21N.2.AHL.TZ0.11a.i:
Find the vector $\vec{AB}$ and the vector $\vec{AC}$ .
21N.2.AHL.TZ0.11a.ii:
Hence find the equation of $Π_{1}$ , expressing your answer in the form $a x + b y + c z = d$ , where $a, b, c, d \in ℤ$ .
21N.2.AHL.TZ0.11d.i:
Find the reflection of the point $B$ in the plane $Π_{3}$ .
21N.2.AHL.TZ0.11d.ii:
Hence find the vector equation of the line formed when $L$ is reflected in the plane $Π_{3}$ .
21N.2.AHL.TZ0.11c.i:
Show that at the point $P, λ = \frac{3}{4}$ .
21N.2.AHL.TZ0.11c.ii:
Hence find the coordinates of $P$ .
18M.1.AHL.TZ2.H_9f.ii:
Find YZ.
19M.1.AHL.TZ1.H_11b:
Verify that ${\text{P}}$ is the point of intersection of the two lines.
18M.1.SL.TZ1.S_9c.ii:
Write down the value of angle OBA.
17M.2.AHL.TZ2.H_9g:
Find the acute angle between the planes Π $_2$ and Π $_3$ .
SPM.2.AHL.TZ0.7:
Two ships, A and B , are observed from an origin O. Relative to O, their position vectors at time t hours after midday are given by

r_A = $\left( {\begin{array}{*{20}{c}} 4 \\ 3 \end{array}} \right) + t\left( {\begin{array}{*{20}{c}} 5 \\ 8 \end{array}} \right)$

r_B = $\left( {\begin{array}{*{20}{c}} 7 \\ { - 3} \end{array}} \right) + t\left( {\begin{array}{*{20}{c}} 0 \\ {12} \end{array}} \right)$

where distances are measured in kilometres.

Find the minimum distance between the two ships.
18M.1.SL.TZ1.S_9b.ii:
Point C (k , 12 , −k) is on L. Show that k = 14.
18M.1.AHL.TZ2.H_9f.i:
Find the coordinates of X, Y and Z.
18M.1.AHL.TZ2.H_9c:
Find the area of the parallelogram ABCD.
18M.1.SL.TZ2.S_1b:
The vector $\left( \begin{gathered} 2 \hfill \\ p \hfill \\ 0 \hfill \\ \end{gathered} \right)$ is perpendicular to $\mathop {{\text{AB}}}\limits^ \to$ . Find the value of p.
20N.1.SL.TZ0.S_7a:
Find an expression for the velocity of $P_{1}$ at time $t$ .
20N.1.SL.TZ0.S_9a:
Express $\vec{AB}$ in terms of $m$ .
EXN.2.AHL.TZ0.11c:
Show that the Cartesian equation of the plane $Π$ that contains the triangle $ABC$ is $- x + y + z = - 2$ .
EXN.2.AHL.TZ0.11d.i:
Find a vector equation of the line $L$ .
17N.1.AHL.TZ0.H_2a:
Find a vector equation of the line L passing through the points A and B.
18N.1.AHL.TZ0.H_9c:
Show that L does not intersect the $y$ -axis for any negative value of $b$ .
17M.2.AHL.TZ2.H_9e:
Verify that 2j + k is perpendicular to the plane Π $_2$ .
17M.1.SL.TZ1.S_8c:
The lines ${L_1}$ and ${L_1}$ intersect at $C(9,{\text{ }}13,{\text{ }}z)$ . Find $z$ .
18M.1.SL.TZ1.S_9c.i:
Find $\mathop {{\text{OB}}}\limits^ \to \, \bullet \mathop {{\text{AB}}}\limits^ \to$ .
18N.1.AHL.TZ0.H_9a:
Find, in terms of $b$ , a Cartesian equation of the plane Π containing this triangle.
20N.1.SL.TZ0.S_9c:
Consider a unit vector $u$ , such that $u = p i - \frac{2}{3} j + \frac{1}{3} k$ , where $p > 0$ .

Point $C$ is such that $\vec{BC} = 9 u$ .

Find the coordinates of $C$ .
EXN.1.AHL.TZ0.8a:
Show that $l_{1}$ and $l_{2}$ are never perpendicular to each other.
17M.1.SL.TZ1.S_8b:
A second line ${L_2}$ , has equation r = $\left( {\begin{array}{*{20}{c}} 1 \\ {13} \\ { - 14} \end{array}} \right) + s\left( {\begin{array}{*{20}{c}} p \\ 0 \\ 1 \end{array}} \right)$ .

Given that ${L_1}$ and ${L_2}$ are perpendicular, show that $p = 2$ .
19M.1.SL.TZ1.S_2a:
Find $c$ .
EXN.2.AHL.TZ0.11e:
Find the volume of right-pyramid $ABCD$ .
17M.1.SL.TZ2.S_9b.ii:
Find $\left| {\overrightarrow {{\text{AB}}} } \right|$ .
21M.1.AHL.TZ2.8a:
Show that $l_{1}$ and $l_{2}$ do not intersect.
21M.1.AHL.TZ1.11c:
It is given that the lines $L_{1}$ and $L_{2}$ have a unique point of intersection, $A$ , when $a \neq k$ .

Find the value of $k$ , and find the coordinates of the point $A$ in terms of $a$ .
21M.1.AHL.TZ2.8b:
Find the minimum distance between $l_{1}$ and $l_{2}$ .
21N.2.AHL.TZ0.11b:
The line $L$ is the intersection of $Π_{1}$ and $Π_{2}$ . Verify that the vector equation of $L$ can be written as $r = (\begin{matrix} 0 \\ - 2 \\ 0 \end{matrix}) + λ (\begin{matrix} 1 \\ 1 \\ - 1 \end{matrix})$ .

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