Date | November 2018 | Marks available | 3 | Reference code | 18N.1.AHL.TZ0.H_9 |
Level | Additional Higher Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 0 |
Command term | Find | Question number | H_9 | Adapted from | N/A |
Question
Consider a triangle OAB such that O has coordinates (0, 0, 0), A has coordinates (0, 1, 2) and B has coordinates (2, 0, − 1) where < 0.
Let M be the midpoint of the line segment [OB].
Find, in terms of , a Cartesian equation of the plane Π containing this triangle.
Find, in terms of , the equation of the line L which passes through M and is perpendicular to the plane П.
Show that L does not intersect the -axis for any negative value of .
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
METHOD 1
(M1)
(M1)A1
(0, 0, 0) on Π so (M1)A1
METHOD 2
using equation of the form (M1)
(0, 1, 2) on Π ⇒
(2, 0, − 1) on Π ⇒ (M1)A1
Note: Award (M1)A1 for both equations seen.
solve for , and (M1)
A1
[5 marks]
M has coordinates (A1)
r = M1A1
Note: Award M1A0 if r = (or equivalent) is not seen.
Note: Allow equivalent forms such as .
[3 marks]
METHOD 1
(M1)
Note: Award M1 for either or or both.
and A1
attempt to eliminate M1
(A1)
A1
EITHER
consideration of the signs of LHS and RHS (M1)
the LHS is negative and the RHS must be positive (or equivalent statement) R1
OR
M1
no real solutions R1
THEN
so no point of intersection AG
METHOD 2
(M1)
Note: Award M1 for either or or both.
and A1
attempt to eliminate M1
(A1)
A1
consideration of the signs of LHS and RHS (M1)
there are no real solutions (or equivalent statement) R1
so no point of intersection AG
[7 marks]