Date | November 2020 | Marks available | 2 | Reference code | 20N.1.SL.TZ0.S_9 |
Level | Standard Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 0 |
Command term | Express | Question number | S_9 | Adapted from | N/A |
Question
Points A and B have coordinates (1, 1, 2) and (9, m, -6) respectively.
The line L, which passes through B, has equation r=(-3-1924)+s(24-5).
Express →AB in terms of m.
Find the value of m.
Consider a unit vector u, such that u=pi-23j+13k, where p>0.
Point C is such that →BC=9u.
Find the coordinates of C.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
valid approach to find →AB (M1)
eg →OB-→OA
A1 N2
[2 marks]
valid approach (M1)
eg
one correct equation (A1)
eg
correct value for A1
eg
substituting their value into their expression/equation to find (M1)
eg
A1 N3
[5 marks]
valid approach (M1)
eg
correct working to find (A1)
eg and
correct approach to find (seen anywhere) A1
eg
recognizing unit vector has magnitude of (M1)
eg
correct working (A1)
eg
A1
substituting their value of (M1)
eg
(accept ) A1 N4
Note: The marks for finding are independent of the first two marks.
For example, it is possible to award marks such as (M0)(A0)A1(M1)(A1)A1 (M0)A0 or (M0)(A0)A1(M1)(A0)A0 (M1)A0.
[8 marks]