Date | May 2015 | Marks available | 3 | Reference code | 15M.1.sl.TZ1.2 |
Level | SL only | Paper | 1 | Time zone | TZ1 |
Command term | Find | Question number | 2 | Adapted from | N/A |
Question
The following diagram shows a circle with centre OO and a radius of 1010 cm. Points AA, BB and CC lie on the circle.
Angle AOBAOB is 1.21.2 radians.
Find the length of arc ACBarc ACB.
Find the perimeter of the shaded region.
Markscheme
correct substitution (A1)
eg10(1.2)10(1.2)
ACBACB is 12 (cm)12 (cm) A1 N2
[2 marks]
valid approach to find major arc (M1)
egcircumference −AB−AB, major angle AOB×radiusAOB×radius
correct working for arc length (A1)
eg2π(10)−12, 10(2×3.142−1.2), 2π(10)−12+202π(10)−12, 10(2×3.142−1.2), 2π(10)−12+20
perimeter is 20π+8(=70.8) (cm)20π+8(=70.8) (cm) A1 N2
[3 marks]
Total [5 marks]
Examiners report
Most candidates were able to find the minor arc length. Similarly most candidates successfully found the major arc length in part b) but did not go on to add the two radii. Quite a few candidates worked with decimal approximations, rather than in terms of ππ.
Most candidates were able to find the minor arc length. Similarly most candidates successfully found the major arc length in part b) but did not go on to add the two radii. Quite a few candidates worked with decimal approximations, rather than in terms of ππ.