Date | May 2009 | Marks available | 5 | Reference code | 09M.2.sl.TZ2.3 |
Level | SL only | Paper | 2 | Time zone | TZ2 |
Command term | Solve | Question number | 3 | Adapted from | N/A |
Question
Solve the equation ex=4sinx , for 0≤x≤2π .
Markscheme
evidence of appropriate approach M1
e.g. a sketch, writing ex−4sinx=0
x=0.371 , x=1.36 A2A2 N2N2
[5 marks]
Examiners report
Although many students started with an analytical approach, many also realized they were not going further and successfully used their GDC to find the intercepts with the x-axis if they had set the equation equal to 0, or in other cases, they found the intersection of the two graphs. The better candidates drew a reasonable sketch and found the two values without difficulty. A good number of candidates did not provide a sketch, however, and they had more trouble earning the mark for showing method. Accuracy penalties were relatively common on this question.