Date | May 2014 | Marks available | 3 | Reference code | 14M.2.sl.TZ2.8 |
Level | SL only | Paper | 2 | Time zone | TZ2 |
Command term | Find | Question number | 8 | Adapted from | N/A |
Question
The number of bacteria in two colonies, AA and BB, starts increasing at the same time.
The number of bacteria in colony AA after tt hours is modelled by the function A(t)=12e0.4tA(t)=12e0.4t.
Find the number of bacteria in colony AA after four hours.
Find the number of bacteria in colony AA after four hours.
How long does it take for the number of bacteria in colony AA to reach 400400?
The number of bacteria in colony BB after tt hours is modelled by the function B(t)=24ektB(t)=24ekt.
After four hours, there are 6060 bacteria in colony BB. Find the value of kk.
The number of bacteria in colony BB after tt hours is modelled by the function B(t)=24ektB(t)=24ekt.
The number of bacteria in colony AA first exceeds the number of bacteria in colony BB after nn hours, where n∈Z. Find the value of n.
Markscheme
correct substitution into formula (A1)
eg 12e0.4(0)
12 bacteria in the dish A1 N2
[2 marks]
correct substitution into formula (A1)
eg 12e0.4(4)
59.4363 (A1)
59 bacteria in the dish (integer answer only) A1 N3
[3 marks]
correct equation (A1)
eg A(t)=400, 12e0.4t=400
valid attempt to solve (M1)
eg graph, use of logs
8.76639
8.77 (hours) A1 N3
[3 marks]
valid attempt to solve (M1)
eg n(4)=60, 60=24e4k, use of logs
correct working (A1)
eg sketch of intersection, 4k=ln2.5
k=0.229072
k=ln2.54 (exact), k=0.229 A1 N3
[3 marks]
METHOD 1
setting up an equation or inequality (accept any variable for n) (M1)
eg A(t)>B(t), 12e0.4n=24e0.229n, e0.4n=2e0.229n
correct working (A1)
eg sketch of intersection, e0.171n=2
4.05521 (accept 4.05349) (A1)
n=5 (integer answer only) A1 N3
METHOD 2
A(4)=59, B(4)=60 (from earlier work)
A(5)=88.668, B(5)=75.446 A1A1
valid reasoning (R1)
eg A(4)<B(4) and A(5)>B(5)
n=5 (integer answer only) A1 N3
[4 marks]