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Date May 2017 Marks available 6 Reference code 17M.2.sl.TZ2.5
Level SL only Paper 2 Time zone TZ2
Command term Find Question number 5 Adapted from N/A

Question

Consider a geometric sequence where the first term is 768 and the second term is 576.

Find the least value of nn such that the nnth term of the sequence is less than 7.

Markscheme

attempt to find rr     (M1)

eg576768, 768576, 0.75576768, 768576, 0.75

correct expression for unun     (A1)

eg768(0.75)n1768(0.75)n1

EITHER (solving inequality)

valid approach (accept equation)     (M1)

egun<7un<7

valid approach to find nn     M1

eg768(0.75)n1=7, n1>log0.75(7768)768(0.75)n1=7, n1>log0.75(7768), sketch

correct value

egn=17.3301n=17.3301     (A1)

n=18n=18 (must be an integer)     A1     N2

OR (table of values)

valid approach     (M1)

egun>7un>7, one correct crossover value

both crossover values, u17=7.69735u17=7.69735 and u18=5.77301u18=5.77301     A2

n=18n=18 (must be an integer)     A1     N2

OR (sketch of functions)

valid approach     M1

egsketch of appropriate functions

valid approach     (M1) 

egfinding intersections or roots (depending on function sketched)

correct value

egn=17.3301n=17.3301     (A1)

n=18n=18 (must be an integer)     A1     N2

[6 marks]

Examiners report

[N/A]

Syllabus sections

Topic 2 - Functions and equations » 2.7 » Solving equations, both graphically and analytically.
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