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Date May 2018 Marks available 4 Reference code 18M.1.sl.TZ2.9
Level SL only Paper 1 Time zone TZ2
Command term Show that Question number 9 Adapted from N/A

Question

A closed cylindrical can with radius r centimetres and height h centimetres has a volume of 20π cm3.

The material for the base and top of the can costs 10 cents per cm2 and the material for the curved side costs 8 cents per cm2. The total cost of the material, in cents, is C.

Express h in terms of r.

[2]
a.

Show that C=20πr2+320πr.

[4]
b.

Given that there is a minimum value for C, find this minimum value in terms of π.

[9]
c.

Markscheme

correct equation for volume      (A1)
eg  πr2h=20π

h=20r2     A1 N2

[2 marks]

 

a.

attempt to find formula for cost of parts      (M1)
eg  10 × two circles, 8 × curved side

correct expression for cost of two circles in terms of r (seen anywhere)      A1
eg  2πr2×10

correct expression for cost of curved side (seen anywhere)      (A1)
eg  2πr×h×8

correct expression for cost of curved side in terms of     A1
eg  8×2πr×20r2,320πr2

C=20πr2+320πr      AG N0

[4 marks]

b.

recognize C=0 at minimum       (R1)
eg  C=0,dCdr=0

correct differentiation (may be seen in equation)

C=40πr320πr2        A1A1

correct equation      A1
eg  40πr320πr2=0,40πr320πr2

correct working     (A1)
eg  40r3=320,r3=8

r = 2 (m)     A1

attempt to substitute their value of r into C
eg  20π×4+320×π2     (M1)

correct working
eg  80π+160π        (A1)

240π (cents)      A1 N3

Note: Do not accept 753.6, 753.98 or 754, even if 240π is seen.

[9 marks]

c.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.

Syllabus sections

Topic 6 - Calculus » 6.2 » Derivative of xn(nQ) , sinx , cosx , tanx , ex and lnx .
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