Date | November 2017 | Marks available | 3 | Reference code | 17N.2.sl.TZ0.1 |
Level | SL only | Paper | 2 | Time zone | TZ0 |
Command term | Find | Question number | 1 | Adapted from | N/A |
Question
The following diagram shows a triangle ABC.
AB=5cm,CˆAB= 50° and AˆCB= 112°
Find BC.
[3]
a.
Find the area of triangle ABC.
[3]
b.
Markscheme
evidence of choosing sine rule (M1)
egsinAa=sinBb
correct substitution (A1)
egBCsin50=5sin112
4.13102
BC=4.13 (cm) A1 N2
[3 marks]
a.
correct working (A1)
egˆB=180−50−112, 18°, AC=1.66642
correct substitution into area formula (A1)
eg12×5×4.13×sin18, 0.5(5)(1.66642)sin50, 12(4.13)(1.66642)sin112
3.19139
area=3.19 (cm2) A1 N2
[3 marks]
b.
Examiners report
[N/A]
a.
[N/A]
b.