In the gas phase, phosphorus pentachloride can be thermally decomposed into gaseous phosphorus trichloride and chlorine.
PCl5 → PCl3 + Cl2
The table below gives the relevant bond energies found in these compounds.
bond
bond energy / kJ mol–1
P–Cl (in both chlorides)
Cl–Cl
What is the enthalpy change in the decomposition of the reaction?
Question 2
Marks: 1
Which equation correctly shows how the bond energy for the covalent bond Y–Z can be calculated by dividing ΔH by n?
nYZ(g) → nY(g) + Z2(g)
Z(g) + YZn-1(g) → YZn(g)
2YZn (g) → 2YZn-1(g) + Y2(g)
YZn(g) → Y(g) + nZ(g)
Question 3
Marks: 1
The diagram shows the skeletal formula of cyclobutane.
The enthalpy change of formation of cyclobutane is +75.1 kJ mol–1, and the enthalpy change of atomisation of graphite is +712 kJ mol–1.
The bond enthalpy of C–H is 414 kJ mol–1 and of H–H is 436 kJ mol–1.
What is the average bond enthalpy of the C–C bond in cyclobutane?
Question 4
Marks: 1
Butane can be produced by the hydrogenation of buta-1,3-diene.
C4H6 (g) + 2H2 (g) → C4H10 (g) ΔH = -248 kJ mol-1
Bond
C-C
C-H
H-H
Mean bond enthalpy / kJ mol-1
346
414
436
Using the information, which calculation shows the bond enthalpy for the C=C bond in buta-1,3-diene?
-248 - ( 2 x 436) + (2 x 346) + (4 x 414)
-124 - 436 + 346 + (2 x 414)
(2 x 346) + (4 x 414) + 248 - (2 x 436)
346 + (2 x 414) + 124 - 436
Question 5
Marks: 1
The equations to form methane and propane from their gaseous atoms are:
C (g) + 4H (g) → CH4 (g) ΔHr = -1656 kJ mol-1
3C (g) + 8H (g) → C3H8 (g) ΔHr = -4004 kJ mol-1
What is the bond enthalpy of a C-C bond?
2002 - 1656
1656 - 2002
Question 6
Marks: 1
Ultraviolet radiation is split into three regions:
UV A (wavelength 400 - 320 nm)
UV B (wavelength 320 - 280 nm)
UV C (wavelength < 280 nm)
High energy photons are present in the solar spectrum at high altitude. The maximum wavelength of a photon that has enough energy to break the O=O bond in oxygen is 240 nm, which is in the UV C region of ultraviolet radiation..
The energy per mole required to break an O=O bond can be calculated using the following equation:
= Energy per bond
Using the supplementary equations c = νλ and E = hν, which is the correct calculation to determine the bond energy of an O=O in kJ mol-1?
Avogadro’s constant = 6.02 x 1023
Planck’s constant = 6.63 x 10-34 J s
Speed of light = 3.00 x 108 m s-1
Question 7
Marks: 1
Which of the following statements about the average bond enthalpy of the halogens are correct?
Fluorine has the highest average bond enthalpy
Average bond enthalpy generally decreases as the size of the atoms increases
In general, increased shielding results in a lower bond enthalpy
I and II only
I and III only
II and III only
I, II and III
Question 8
Marks: 1
What is the correct order to show the decreasing strength of the F-H, N-H and O-H bonds?
N-H > O-H > F-H
O-H > N-H > F-H
F-H > N-H > O-H
F-H > O-H > N-H
Question 9
Marks: 1
Water has two different bond enthalpies for the two O-H bonds that it contains:
H2O (g) → H (g) + OH (g) ΔH = +502 kJ mol-1
OH (g) → H (g) + O (g) ΔH = +427 kJ mol-1
The average O-H bond enthalpy from an accepted data table is 463 kJ mol-1.
Which calculation correctly shows the percentage difference between the average O-H bond enthalpy of water and the data table average bond enthalpy value?
Question 10
Marks: 1
Some of the reactions involved in the formation and depletion of ozone are: