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Date May 2017 Marks available 2 Reference code 17M.1.sl.TZ2.6
Level SL only Paper 1 Time zone TZ2
Command term Find Question number 6 Adapted from N/A

Question

For a study, a researcher collected 200 leaves from oak trees. After measuring the lengths of the leaves, in cm, she produced the following cumulative frequency graph.

M17/5/MATSD/SP1/ENG/TZ2/06

The researcher finds that 10% of the leaves have a length greater than \(k\) cm.

Write down the median length of these leaves.

[1]
a.

Write down the number of leaves with a length less than or equal to 8 cm.

[1]
b.

Use the graph to find the value of \(k\).

[2]
c.i.

Before measuring, the researcher estimated \(k\) to be approximately 9.5 cm. Find the percentage error in her estimate.

[2]
c.ii.

Markscheme

9 (cm)     (A1)     (C1)

[1 mark]

a.

40 (leaves)     (A1)     (C1)

[1 mark]

b.

\((200 \times 0.90 = ){\text{ }}180\) or equivalent     (M1)

 

Note:     Award (M1) for a horizontal line drawn through the cumulative frequency value of 180 and meeting the curve (or the corresponding vertical line from 10.5 cm).

 

\((k = ){\text{ }}10.5{\text{ (cm)}}\)     (A1)     (C2)

 

Note:     Accept an error of ±0.1.

 

[2 marks]

c.i.

\(\left| {\frac{{9.5 - 10.5}}{{10.5}}} \right| \times 100\% \)     (M1)

 

Notes:     Award (M1) for their correct substitution into the percentage error formula.

 

\({\text{9.52 (% ) }}\left( {{\text{9.52380}} \ldots {\text{ (% )}}} \right)\)     (A1)(ft)     (C2)

 

Notes:     Follow through from their answer to part (c)(i).

Award (A1)(A0) for an answer of \( - 9.52\) with or without working.

 

[2 marks]

c.ii.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.i.
[N/A]
c.ii.

Syllabus sections

Topic 1 - Number and algebra » 1.2
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