| Date | November 2010 | Marks available | 2 | Reference code | 10N.1.sl.TZ0.3 |
| Level | SL only | Paper | 1 | Time zone | TZ0 |
| Command term | Find | Question number | 3 | Adapted from | N/A |
Question
In a television show there is a transparent box completely filled with identical cubes. Participants have to estimate the number of cubes in the box. The box is 50 cm wide, 100 cm long and 40 cm tall.
Find the volume of the box.
Joaquin estimates the volume of one cube to be 500 cm3. He uses this value to estimate the number of cubes in the box.
Find Joaquin’s estimated number of cubes in the box.
The actual number of cubes in the box is 350.
Find the percentage error in Joaquin’s estimated number of cubes in the box.
Markscheme
\(50 \times 100 \times 40 = 200\,000{\text{ c}}{{\text{m}}^3}\) (M1)(A1) (C2)
Note: Award (M1) for correct substitution in the volume formula.
[2 marks]
\(\frac{{200\,000}}{{500}} = 400\) (M1)(A1)(ft) (C2)
Note: Award (M1) for dividing their answer to part (a) by 500.
[2 marks]
\(\frac{{400 - 350}}{{350}} \times 100 = 14.3{\text{ }}\% \) (M1)(A1)(ft) (C2)
Notes: Award (M1) for correct substitution in the percentage error formula.
Award (A1) for answer, follow through from part (b).
Accept –14.3 %.
% sign not necessary.
[2 marks]
Examiners report
This question proved to be the one that most candidates answered correctly. Many received full marks and the only error seen was incorrect substitution in the percentage error formula.
This question proved to be the one that most candidates answered correctly. Many received full marks and the only error seen was incorrect substitution in the percentage error formula.
This question proved to be the one that most candidates answered correctly. Many received full marks and the only error seen was incorrect substitution in the percentage error formula.
